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klemol [59]
3 years ago
8

Which of the following represent chemical processes? Which represent physical processes?

Chemistry
1 answer:
Viktor [21]3 years ago
7 0

Answer:

A). Calcium chloride dihydrate (CaCl2 * 2H2O) slowly heated in a crucible to become calcium chloride (anhydrous).

Dehyration is a physical process

B). A hydrocarbon such as propane (C3H8) undergoes combustion to power a grill

Combustion is a chemical process.

C). A rock climber’s rope becomes frayed and turns the color of the rocks

This is physical process

D). A dog urinates on an air conditioner coil and the coil becomes corroded

Corrsion is a chemical process.

Explanation:

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Answer:

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Explanation:

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A welding tank of oxygen gas has a volume of 100. L. The oxygen in the tank is at a pressure of 95 atm and a temperature of 30.
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NEED HELP with 7. 8. 9. 10. 11. 12. And 14 !!
aleksley [76]

Answer:

1.      0.00040 calories

2.   8.57 calories

3.   0.196 calories

4.  68 calories

5. 243 calories

6.  83680 joules

7.  1,054,368 joules

8. 2.45 calories

9. 556 (it says calories to calories so it wouldn't change)

10. 28367.52 joules

11. 59.6 calories

12. 449.6 joules

13.  0.00234 calories

14. 23292.328 joules

15. 22877693.6 joules

Hope this helps!

Explanation:

6 0
3 years ago
DO NOT ANSWER IF YOU DO NOT KNOW WHAT TO DO
Mice21 [21]

Answer:

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4 0
3 years ago
Read 2 more answers
Nh3 is a weak base (kb = 1.8 × 10–5 m) and so the salt nh4cl acts as a weak acid. what is the ph of a solution that is 0.013 m i
ankoles [38]
First, we need to get the value of Ka:

when Ka = Kw / Kb 

we have Kb = 1.8 x 10^-5 

and Kw = 3.99 x 10^-16  so, by substitution:

Ka = (3.99 x 10^-16) /  (1.8 x 10^-5) = 2.2 x 10^-11

by using the ICE table :

                 NH4+  + H2O →NH3 +  H+
intial          0.013                       0         0 

change       -X                          +X      +X

Equ        (0.013-X)                      X         X

when Ka = [NH3][H+] / [NH4+] 

by substitution:

2.2 x 10^-11 = X^2 / (0.013 - X)  by solving this equation for X

∴X = 5.35 x 10^-7

∴[H+] = X = 5.35 x 10^-7

∴PH = - ㏒[H+]
 
        = -㏒(5.35 x 10^-7)
        = 6.27
6 0
3 years ago
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