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Zepler [3.9K]
3 years ago
9

SUBJECT: ASTRONOMY -- TOPIC: Time Dilation

Physics
1 answer:
inessss [21]3 years ago
3 0

Answer:

You can determine if the ship is moving by lying down and measuring your height.

Explanation:

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How are all paths that have a displacement of zero similar??
alex41 [277]
Displacement is known as the net movement of an object with respect to its original position. One may travel out of his city and return. Despite having covered many miles, he will have have a displacement of 0.
This is true for all paths that have zero displacement, that they all return to their original position.
6 0
3 years ago
Read 2 more answers
Two rings of radius 5 cm are 20 cm apart and concentric with a common horizontal x-axis. The ring on the left carries a uniforml
Yanka [14]

Answer:

The electric field due to the right ring at a location midway between the two rings is 2.41\times10^{3}\ V/m

Explanation:

Given that,

Radius of first ring = 5 cm

Radius of second ring = 20 cm

Charge on the left of the ring = +30 nC

Charge on the right of the ring = -30 nC

We need to calculate the electric field due to the right ring at a location midway between the two rings

Using formula of  electric field

E=\dfrac{1}{4\pi\epsilon_{0}}\times\dfrac{qx}{(x^2+R^2)^{\frac{3}{2}}}

Put the value into the formula

E=\dfrac{9\times10^{9}\times30\times10^{-9}\times0.1}{((0.1)^2+(0.2)^2)^{\frac{3}{2}}}

E=2.41\times10^{3}\ V/m

Hence, The electric field due to the right ring at a location midway between the two rings is 2.41\times10^{3}\ V/m

3 0
4 years ago
Activity: Brigada Tahanan, "Pamilyang namamahalan, Sa paglilinis sama-sama"
Dimas [21]

Answer:

WOW YOU SPEAK BEAUTIFUL MANDARIN

5 0
3 years ago
What is the direction of a vector with an x component of -12 m and a y component of 21 m?
Svet_ta [14]

Answer:

Direction= 119.74^\circ

Explanation:

<u>Displacement Vector</u>

The displacement, as every vector, has a magnitude r and a direction angle θ measured from the positive x-axis.

If we know the x-y components of the displacement, the magnitude and angle can be calculated by the equations:

r=\sqrt{x^2+y^2}

\displaystyle \tan\theta=\frac{y}{x}

The coordinates of the given vector are x=-12 m, y=21 m, thus:

\displaystyle \tan\theta=\frac{21}{-12}=-1.75

\theta=tan^{-1}(-1.75)=-60.26^\circ

Since the vector lies in the second quadrant, we add 180° to find the correct direction:

\boxed{Direction=-60.26^\circ+180^\circ= 119.74^\circ}

4 0
3 years ago
The water table is the upper limit of the
Furkat [3]

Answer:

zone of saturation

Explanation:

The water table is the upper limit of the zone of saturation. At the zone of saturation, the aquifers are filled with water completely. The void spaces within the rock particles are taken up by fluids.

The upper limit of this zone is the water table.

Above the water table is the zone of aeration where the pore spaces are filled within air.

During the time of recharge especially raining seasons, part of the zone of aeration are filled with water.

3 0
3 years ago
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