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3 years ago

SUBJECT: ASTRONOMY -- TOPIC: Time Dilation

Physics

1 answer:

inessss [21]3 years ago

3 0

Answer:

You can determine if the ship is moving by lying down and measuring your height.

Explanation:

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PLEASE HURRYYYYY!!

lara [203]

Answer:1st

Explanation:and object in motion stays in motion unless acted upon by another object

5 0

3 years ago

Why do the heights of the tides change over the course of a month?

Y_Kistochka [10]

Answer:

The heights of the tides change over the course of a month due to -

<u>the position of Sun , Moon and Earth .</u>

Explanation:

Tides are formed due to the gravitational attraction of the sun and the moon on the surface of the Earth .

Since , the Moon is closer to Earth as compared to the Sun , Hence , Moon has greater attraction on Earth than Sun .

Moon plays an important role for producing the Tides .

In every 27.3 days , the Earth and the Moon revolves around the common point .

Therefore , in every 27.3 days , a new tidal cycle forms .

Two types of tides are possible , high tide and low tides .

In a day , two high tide and two low tide occurs ,

And because of the angle of Moon with respect to Earth , the two high tides do not have the same height . same for the case of two low tide .

The height of tides differ in the height on a daily basis .

5 0

3 years ago

Which of the following would increase the output force of a lever?

Vedmedyk [2.9K]

A. Increase the distance between the effort and the fulcrum

5 0

3 years ago

An ipod uses a standard 1.7 volt battery. How much resistance is in the circuit if it uses a current of 0.03 amps

natali 33 [55]

Answer:

R = V ÷ I = 1.5V ÷ 0.01A = 150Ω

Explanation:

150 is the answer:)

7 0

3 years ago

A mass weighting 48 lbs stretches a spring 6 inches. The mass is in a medium that exerts a viscous resistance of 27 lbs when the

Mademuasel [1]

Answer:

$u(t)=0.499ft.e^{-\frac{144.76lb/s}{2(48lb)}t}cos(\omega t)\\\\u(t)=0.499ft.e^{-1.5t}cos(\omega t)$

m = 48lb

b = 144.76lb

Explanation:

The general equation of a damping oscillate motion is given by:

$u(t)=u_oe^{-\frac{b}{2m}t}cos(\omega t-\alpha)$ (1)

uo: initial position

m: mass of the block

b: damping coefficient

w: angular frequency

α: initial phase

a. With the information given in the statement you replace the values of the parameters in (1). But first, you calculate the constant b by using the information about the viscous resistance force:

$|F_{vis}|=bv\\\\b=\frac{|F_{vis}|}{v}\\\\|F_{vis}|=27lbs=27*32.17ft.lb/s^2=868.59ft.lb/s^2\\\\b=\frac{868.59}{6}lb/s=144.76lb/s$

Then, you obtain by replacing in (1):

6in = 0.499 ft

$u(t)=0.499ft.e^{-\frac{144.76lb/s}{2(48lb)}t}cos(\omega t)\\\\u(t)=0.499ft.e^{-1.5t}cos(\omega t)$

mass, m = 48lb

b = 144.76 lb/s

8 0

3 years ago