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2 years ago

A car weighing 14,700 N is speeding down a highway with a velocity of 99 km/h. What is the

Physics

1 answer:

tankabanditka [31]2 years ago

7 0

Answer: 148348.6239 kg•m/s

Explanation: Firstly, we need to convert the 14700 N into kilograms, and to do so, use the formula net force is equal to mass times acceleration and rearrange the formula to find mass like shown below...

F = ma

F/a = m

14700/9.81 = 1498.470948 kg, this is your mass

Now that we convert it into kilograms, plug all the numbers into the variable of the momentum formula.

Momentum formula is P = mass x velocity

Like this:

P = 1498.470948 x 99

p = 148348.6239 kg•m/s.

I believe that is your answer, hope that helps you even a bit out.

Thanks.

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Radiation can carry thermal energy.

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4 years ago

Monochromatic light from a distant source is incident on a slit 0.705 mm wide. On a screen 2.13 m away, the distance from the ce

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492.183 nm

Explanation:

x = Distance from the central maximum to the first minimum = 1.35 mm

l = Distance of screen = 2.13 m

d = Distance of gap = 0.705 mm

m = Order = 1

We have the relation

$tan\theta=\dfrac{x}{l}\\\Rightarrow \theta=tan^{-1}\dfrac{1.35\times 10^{-3}}{2.13}\\\Rightarrow \theta=0.04^{\circ}$

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The wavelength of the light is 492.185 nm

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3 years ago

Read 2 more answers

A convex refracting surface has a radius of 12 cm. Light is incident in air (n = 1) and refracted into a medium with an index of

OLga [1]

Answer:

<h2>36cm from the surface</h2>

Explanation:

Equation of refraction of a lens is expression according to the formula given below;

$\dfrac{n_2}{v} = \dfrac{n_1}{u}= \dfrac{n_2-n_1}{R}$

R is the radius of curvature of the convex refracting surface = 12cm

v is the image distance from the refracting surface

u is the object distance from the refracting surface

n₁ and n₂ are the refractive indices of air and the medium respectively

Given parameters

R = 12 cm

u = $\infty$ (since light incident is parallel to the axis)

n₁ = 1

n₂ = 1.5

Required

<em>focus point of the light that is incident and parallel to the central axis (v)</em>

<em />

Substituting this values into the given formula we will have;

$\dfrac{1.5}{v} - \dfrac{1}{\infty}= \dfrac{1.5-1}{12}\\\\\dfrac{1.5}{v} -0= \dfrac{0.5}{12}\\\\\dfrac{1.5}{v}= \dfrac{0.5}{12}\\\\$

Cross multiply

$1.5*12 = 0.5*v\\ \\18 = 0.5v\\\\v = \frac{18}{0.5}\\ \\v = 36cm$

Hence Light incident parallel to the central axis is focused at a point 36cm from the surface

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3 years ago

Even though petrol and water are liquids,what is different you observed between them?

stellarik [79]

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3 years ago

A high-performance sports car can go from 0 to 100 mph in 5.8 s. (Assume the car travels in the positive direction. Indicate the

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Initial velocity (u) = 0, final velocity (v) = 44.71 m/s, t = 5.8s, a = acceleration =?

By using newton's laws of motion

v = u + at

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44.71 = 5.8a

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Question b)

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Hence u = 34 m/s, v = 0, a =?, t = 5.1 s

v = u + at

0 = 34 + a(5.1)

a(5.1) = - 34

a = - 34/5.1

a = - 6.67 m/s².

The negative sign beside the acceleration shows that the body is decelerating

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3 years ago