Answer:
By turning the vehicle "ON" position you can check to see if the gauges light works.
When we switch ON or turn a key to ON the engine, we can find all the gauges working or not.
Answer:
3.75 m/s^2
Explanation:
The centripetal acceleration of an object in uniform circular motion is given by the equation:
where
v is the tangential speed of the object
r is the radius of the trajectory
In this problem, r = 60 m and v = 15 m/s, therefore the centripetal acceleration of the car is
Xrayssssss because they are the closest to gamma rays, and they have the highest frequency
Electromagnetic waves<span> differ from mechanical </span>waves<span> in that they </span>do<span> not require a </span>medium<span> to propagate. This means that electromagnetic </span>waves<span> can </span>travel<span> not only </span>through<span> air and solid materials, but also </span>through<span> the vacuum of space.</span>
Answer:
The speed of the car at the end of the 2nd second = 8.0 m/s
Explanation:
The equations of motion will be used to solve this problem.
A car starts from rest,
u = initial velocity of the car = 0 m/s
Accelerates at a constant rate in a straight line,
a = constant acceleration of the car = ?
In the first second the car moves a distance of 2.0 meters,
t = 1.0 s
x = distance covered = 2.0 m
x = ut + (1/2)at²
2 = 0 + (1/2)(a)(1²)
a = 4.0 m/s²
How fast will the car be moving at the end of the second second
Now,
a = 4.0 m/s²
u = initial velocity of the car at 0 seconds = 0 m/s
v = final velocity of the car at the end of the 2nd second = ?
t = 2.0 s
v = u + at
v = 0 + (4×2)
v = 8.0 m/s