I’m standard form it will be 11570000 KL or in scientific notation 1.157x10^7
Explanation:
According to mass action,
![\textrm{rate}=-\dfrac{\Delta[\textrm A]}{2\Delta t}=k[\textrm A]^2](https://tex.z-dn.net/?f=%5Ctextrm%7Brate%7D%3D-%5Cdfrac%7B%5CDelta%5B%5Ctextrm%20A%5D%7D%7B2%5CDelta%20t%7D%3Dk%5B%5Ctextrm%20A%5D%5E2)
Where, k is the rate constant
So,
![\dfrac{d[A]}{dt}=-k[A]^2](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%5BA%5D%7D%7Bdt%7D%3D-k%5BA%5D%5E2)
Integrating and applying limits,
![\int_{[A_t]}^{[A_0]}\frac{d[A]}{[A]^2}=-\int_{0}^{t}kdt](https://tex.z-dn.net/?f=%5Cint_%7B%5BA_t%5D%7D%5E%7B%5BA_0%5D%7D%5Cfrac%7Bd%5BA%5D%7D%7B%5BA%5D%5E2%7D%3D-%5Cint_%7B0%7D%5E%7Bt%7Dkdt)
we get:
![\dfrac{1}{[A]} = \dfrac{1}{[A]_0}+kt](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B%5BA%5D%7D%20%3D%20%5Cdfrac%7B1%7D%7B%5BA%5D_0%7D%2Bkt)
Where,
![[A_t]](https://tex.z-dn.net/?f=%5BA_t%5D)
is the concentration at time t
![[A_0]](https://tex.z-dn.net/?f=%5BA_0%5D)
is the initial concentration
Half life is the time when the concentration reduced to half.
So, ![[A_t]=\frac{1}{2}\times [A_0]](https://tex.z-dn.net/?f=%5BA_t%5D%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%5BA_0%5D)
Applying in the equation as:
![t_{1/2}=\dfrac{1}{k[A_o]}](https://tex.z-dn.net/?f=t_%7B1%2F2%7D%3D%5Cdfrac%7B1%7D%7Bk%5BA_o%5D%7D)
True, in space the tail of a comet will be cold since it a. doesnt have a hot core and b. are typically not found near the sun
Answer:
Properties
Explanation:
Mendeleev realized that the physical and chemical properties of elements were related to their atomic mass in a 'periodic' way, and arranged them so that groups of elements with similar properties fell into vertical columns in his table.
Answer:
46 g of sodium
Explanation:
Sodium reacts vigorously with fluoride gas to form NaF as shown
2Na (s) + F2 (g) ------> 2NaF (s) (Na = 23, F = 19)
2 moles of Na reacts with 1 mole of F2 to produce NaF
By calculating the molar mass of the elements involved in the reaction then multiplied by the mole, the mass can be obtained.
23 * 2 g/mol of Na reacts with 1 * 19 g/mol of F2
46 g/mol of Na reacts with 19 g/mol of F2 to produce NaF
Since the mole ratio is 2 to 1 and 19 g of F2 is used for the reaction, 46 g of sodium will be consumed for the reaction to be achieved.
