<u>Answer:</u>
<u>For 1:</u> The percentage composition of
in unknown carbonate sample is 31.79 %
<u>For 2:</u> The unknown carbonate sample is potassium carbonate.
<u>Explanation:</u>
To calculate the percentage composition of carbon dioxide in sample, we use the equation:
.....(1)
Mass of sample = 1.1000 g
Mass of carbon dioxide = 0.3497 g
Putting values in equation 1, we get:

Hence, the percentage composition of
in unknown carbonate sample is 31.79 %
We are given:
Mass of carbon dioxide = ![[1\times 12.01)+(2\times 16.00)]=44.01g](https://tex.z-dn.net/?f=%5B1%5Ctimes%2012.01%29%2B%282%5Ctimes%2016.00%29%5D%3D44.01g)
- <u>For lithium carbonate:</u>
Mass of lithium carbonate= 73.892 g
Mass of carbon dioxide = 44.01 g
Putting values in equation 1, we get:

The percent composition of carbon dioxide in lithium carbonate is 59.55 %
- <u>For potassium carbonate:</u>
Mass of potassium carbonate= 138.21 g
Mass of carbon dioxide = 44.01 g
Putting values in equation 1, we get:

The percent composition of carbon dioxide in potassium carbonate is 31.84 %
- <u>For sodium carbonate:</u>
Mass of sodium carbonate= 105.99 g
Mass of carbon dioxide = 44.01 g
Putting values in equation 1, we get:

The percent composition of carbon dioxide in sodium carbonate is 41.52 %
- <u>For calcium carbonate:</u>
Mass of calcium carbonate = 100.09 g
Mass of carbon dioxide = 44.01 g
Putting values in equation 1, we get:

The percent composition of carbon dioxide in calcium carbonate is 43.97 %
As, the percent composition of carbon dioxide in the unknown sample matches the percent composition of carbon dioxide in potassium carbonate.
Hence, the unknown carbonate sample is potassium carbonate.