Initial launch velocity, u = 0
Acceleration, a = 300 m/s²
Duration, t = 8.0 s
The distance traveled is
h = ut + (1/2)*a*t²
= (0 m/s)*(8 s) + 0.5*(300 m/s²)*(8 s)²
= 9600 m
Answer: 9600 m
That ratio is the efficiency of whatever the power went into and came out of. There's no reason the efficiency has to be expressed as a percentage.
Answer:
5 m
Explanation:
First, we need to find the distance traveled by car in the 0.50 s:
Now, we can find the distance traveled by car when the brakes are applied:
Finally, the distance between the car and the deer is:
Therefore, the distance between the car and the deer is 5 m.
I hope it helps you!
Volume of a cube = Side^3 = side x side x side
Volume = 3.50 x 3.50 x 3.50 = 42.875 mm^3
Answer: When the worker is on the top rung
Explanation: When the ladder was initially resting on the wall, the torque from the normal reaction on ladder from the horizontal surface is equal to the torque from the vertical surface on ladder.
The weight of the worker produces a torque which is in the direction of the torque from the normal reaction on ladder, produced by the vertical surface. Therefore for the ladder to stay in rotational equilibrium, the torque on ladder from the normal reaction produced by the horizontal surface must increase.
This increase is possible when the worker is on the lower rung, but as the worker goes high, the magnitude of normal reaction from the vertical surface would increase, thereby increasing the risk of slipping of ladder.