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Charra [1.4K]
3 years ago
12

Which factor contributes the most to the process of water erosion?

Physics
2 answers:
asambeis [7]3 years ago
6 0
The answer is b or d u chooose i don’t know which one
MrRa [10]3 years ago
5 0

Answer:

Evaporation

Explanation:

Erosion is a natural process, but human activity can make it happen more quickly. Human activity altering the vegetation of an area is perhaps the biggest human factor contributing to erosion. Trees and plants hold soil in place.

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Why is it impossible to create a perpetual motion machine?
Tatiana [17]

Answer:

It is impossible to create a perpetual motion machine because some of the energy will always be lost in the conversion  and therefore it will eventually stop.

Correct Answer : Option B

Explanation:

The perpetual motion machine is impossible machine as it is hypothetical working machine which would be in motion for an indefinite time in continuity of the motion. The continuity of motion for an indefinite time would mean that the working principle of the machine would never allow the dissipation of energy from the machine and all the machine would ultimately reserve all the energy and be converting it into forms without any loss.

This working principle is violation of first and second laws of thermodynamics and hence a machine will eventually lose some of its energy in every conversion of the working cycle and hence there will be a time where the machine would be stopped, and hence a perpetual motion machine cannot be made.

8 0
3 years ago
A buoy is a floating device that can have many purposes, but often as a locator for ships. Collin constructs a hollow metal buoy
Yuri [45]

Answer:

A) since the density of the buoy is half the density of sea water when the buoy is at rest on an ocean half of the buoy will be submerged in water

B )angular frequency ( w ) = \sqrt{\frac{3g}{h} }

c )  h = 1.34 m ( 4\pi ^{2} / 3g )

Explanation:

A) since the density of the buoy is half the density of sea water when the buoy is at rest on an ocean half of the buoy will be submerged in water this is because the substances with lesser density floats when placed in a substance with a higher density

B ) when the Buoy is at rest ( t = 0 ) and is then pushed down calculate angular frequency ( w ) of small oscillations in terms of the given variables

volume of cone = hA /3.

h = height of cone, A = Base Area.

therefore the total volume of the Buoy above water level ( at rest )

= (\pi r^{2} * \frac{h}{3} ) * 2 = \frac{\pi r^{2} h  }{6}

The  part of the buoy immersed in water = x

then the net upward force will be

fb ( force of Buoy ) =  fg ( force of gravity )

note force = Mass * Acceleration

force of buoy = \frac{\alpha }{2} *\frac{\pi r^{2}  }{h}* a = ( force of gravity ) \alpha * T\frac{r^{2} }{4} * x * g

therefore a = \frac{3g}{h}  * x

angular frequency ( w ) = \sqrt{\frac{3g}{h} }

C ) height of the each cone

\frac{2\pi }{w}  = 1 therefore w = 2\pi

back to the angular frequency : \frac{3g}{h} = 4\pi ^{2}

therefore h = 1.34 m ( 4\pi ^{2} / 3g )

4 0
3 years ago
Four students are each pushing on one side of a box. Mara is pushing to the west, Cindi is pushing to the east, Chris is pushing
jenyasd209 [6]

Answer:

cindi

Explanation:

cindi's work done is larger than all the other students combined

5 0
2 years ago
A fire engine is moving south at 35 m/s while blowing its siren at a frequency of 400 Hz.
vodomira [7]

To solve this problem we will apply the concepts related to the Doppler effect. The Doppler effect is the change in the perceived frequency of any wave movement when the emitter, or focus of waves, and the receiver, or observer, move relative to each other. Mathematically it can be described as

f_d= f_s \frac{(v+v_d)}{(v-v_s)}

Here,

f_d=frequency received by detector

f_s=frequency of wave emitted by source

v_d=velocity of detector

v_s=velocity of source

v=velocity of sound wave

Replacing we have that,

f_d = 400(\frac{(343+18)}{(343-35)})

f_d=422 Hz

Therefore the frequencty that will hear the passengers is 422Hz

8 0
3 years ago
a 3,000kg truck runs into the rear of a 1000kg car that was stationary. The truck and car are locked together after the collisio
joja [24]
FVJDJFN.s<ldF KN,M c":F,BJ TNHIJRT IHJYODIFG 
7 0
3 years ago
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