Answer:
Explanation:
Given
Inclination 
Distance of landing point 
Considering athlete to be an Projectile
range of projectile is given by
where u=launch velocity
(b)If u is increased by 8% then
new velocity is 
Answer:
<em>Asha traveled a distance of 50 m</em>
<em>The displacement is 20 m north.</em>
Explanation:
<u>Distance and Displacement
</u>
A moving object constantly travels for some distances at defined periods of time. The total moved distance is the sum of each individual distance the object traveled. It can be written as:
dtotal=d1+d2+d3+...+dn
This sum is obtained independently of the direction the object moves.
The displacement only takes into consideration the initial and final positions of the object while moving. The displacement, unlike distance, is a vectorial magnitude and can even have magnitude zero if the object starts and ends the movement at the same point.
Asha walks 15 m west, 20 m north, and 15 m east. The total distance is
dt=15 m + 20 m + 15 m = 50 m
Asha traveled a distance of 50 m
Note the final position is 20 m above the initial position since she goes 15 m west and 15 m east. Thus the displacement is 20 m north.
What diagram I can't find it.
Answer:
kE=1/2mv^2
Explanation:
here
KE= 15000j
velocity =20m/s
mass=?
now
mass=
15000×2= (m)20^2
30000=m ×400
30000÷400=m
Mass (m)= 75
therefore mass is 75kilogram
