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k0ka [10]
3 years ago
7

Another method in creating a temporary magnet is by using electricity. This can be done by wrapping an iron nail with a coil of

wire. By passing electricity through the coil of wire the iron nail will become a temporary magnet or an electromagnet. The strength of the electromagnet depends on the size of the electric current and the number of times the coil is wrapped around the nail. If the electricity stops flowing through the coil the nail will no longer be magnetic.
Write a one sentence summary of the above paragraph.
Physics
1 answer:
sukhopar [10]3 years ago
3 0

One method of creating a magnet is coiling wire around a nail and running electricity through it, to make the magnet stronger coil more wire and increase the Voltage.

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Ms. Mary Mack walked around her block from her house for 200 meters. She arrived back at her house in 15 minutes. What was her d
inysia [295]

Answer:

d = 0 [m]

Explanation:

Displacement is understood as the length and direction that a body travels to move from an initial point to an endpoint.

This displacement is represented with a vector or straight line that indicates the distance of the displacement and its length.

This displacement in an easier way to understand. It is the distance between the start point and the endpoint of the journey. Since the second point is equal to the first point, since Mary returns to the same place, there is no difference between the displacement.

Therefore the displacement is zero.

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A motorcycle accelerates from at a rate of 4m/s 2 while traveling 60m what it’s the motorcycles velocity at the end of this moti
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Answer: C

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Compressing the air by squeezing the bottle was accompanied by a(n) ________ in the temperature of air inside the bottle
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3 years ago
When light of wavelength 240 nm falls on a potassium surface, electrons having a maximum kinetic energy of 2.93 eV are emitted.
olchik [2.2K]

A) We want to find the work function of the potassium. Apply this equation:

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Given values:

E = 2.93eV, λ = 240nm

Plug in and solve for Φ:

2.93 = 1243/240 - Φ

Φ = 2.25eV

B) We want to find the threshold wavelength, i.e. find the wavelength such that the energy E of the photoelectrons is 0eV. Plug in E = 0eV and Φ = 2.25eV and solve for the threshold wavelength λ:

E = 1243/λ - Φ

0 = 1243/λ - Φ

0 = 1243/λ - 2.25

λ = 552nm

C) We want to find the frequency associated with the threshold wavelength. Apply this equation:

c = fλ

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Given values:

c = 3×10⁸m/s, λ = 5.52×10⁻⁷m

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3×10⁸ = f(5.52×10⁻⁷)

f = 5.43×10¹⁴Hz

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3 years ago
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