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Bumek [7]
3 years ago
15

Why might a plant that normally grows in one environment not grow well in a different one?

Physics
1 answer:
disa [49]3 years ago
3 0
A plant that normally grows in one environment not grow well in a different environment because every flower is different around the certain providing environment.
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old stars obtain part of their energy by the fusion of three alpha particles to form a 12/6c nucleus, whose mass is 12.0000 u. H
marta [7]

Answer:

11.6532 x 10⁻¹¹ J or 7.3 MeV is given off

Explanation:

Mass of an alpha particle = 4.0026u,   ∴ mass of three = 12.0078u

Find the difference in mass.

Mass of three alpha - Mass of Carbon nucleus

12.0078u - 12u = 0.0078u

Since 1u = 1.66 x 10⁻²⁷ kg

Therefore, 0.0078u = 1.2948 x 10⁻²⁷

Now that we know Mass(m) = 1.2948 x 10⁻²⁷ and Speed (c) 3 x 10⁸ m²s⁻²

Formular for Energy ==> E₀ = mc²

E = (1.2948 x 10⁻²⁷) (3 x 10⁸ m²s⁻²)²

E = (1.2948 x 10⁻²⁷) (9 x 10¹⁶) J

E = 11.6532 x 10⁻¹¹ J

Or, if you need your energy in MeV

1 MeV = 1.60x10⁻¹³ J

Just do the conversion by dividing 11.6532 x 10⁻¹¹ J by 1.60x10⁻¹³ J

It will give you 7.3 MeV

7 0
3 years ago
During skidding of a vehicle, wheel moves ___________ rotation.
wariber [46]

Answer:

c it does not move as the tire stops and applys friction

Explanation:

6 0
3 years ago
Example of optical object​
Alik [6]

Answer:

Telescope,cameras

Hope it helped

5 0
3 years ago
Read 2 more answers
Which of the following is an example of an indirect tax?
Brrunno [24]

Answer:Sales tax, value-added tax, excise tax, and customs duties are examples of indirect taxes.

Explanation:

4 0
3 years ago
A loudspeaker having a diaphragm that vibrates at 910 Hz is traveling at 75.0 m/s directly toward a pair of holes in a very larg
Alina [70]

To solve this problem we need to apply doppler equation,

Our values are:

f_0 = 910Hz\\c = 75m\\v=344m/s\\\theta= 12.9\°\\

Doppler equation is given by,

f= \frac{v}{v-c} f_0

Substituting,

f= \frac{344}{344-75}*910

f = 1163Hz

\lambda = \frac{344}{1163}

Wavelenght is equal to,

\lambda = \frac{c}{f}

\lambda = 0.2956

We can now find the distance by,

d= \frac{1}{2}\frac{\lambda}{sin\theta}

d=\frac{1}{2}\frac{0.2956}{sin(12.9)}

d= 0.66m

b) We can find at what angles would sound first cancel through the same equation of wavelenght,

\lambda = \lambda{c}{f} = \frac{344}{1163}

d* sin\theta = \frac{1}{2}*\lambda

\theta = arcsin( 0.5*(344/1163)/0.66)=12.94\°

5 0
3 years ago
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