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Blababa [14]
2 years ago
10

A coach shouts "Go!" from the finish line of a 100.0-m track to the runners.

Physics
1 answer:
irina [24]2 years ago
5 0

Answer:

a. Speed = 342.5 meters per seconds.

b. Wavelength = 2.0 meters

Explanation:

Given the following data;

Distance = 100m

Time = 292 milliseconds to seconds = 292/1000 = 0.292 seconds

Frequency = 171 Hz

a. To find the speed of sound in air;

Speed = distance/time

Speed = 100/0.292

Speed = 342.5 m/s

b. To find the wavelength;

Wavelength = speed/frequency

Wavelength = 342.5/171

Wavelength = 2.0 m

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3 years ago
You are spinning a rock, of mass 0.75 kg, at the end of a string of length 0.86m in a vertical circle in uniform circular motion
Nina [5.8K]

Answer:

v (minimum speed) = 2.90 m/sec.

\\ \\ maximum speed (v)= 6.57 m/sec.\\

Maximum value of speed will occur at lowest point of vertical circle.

Explanation:

a)  What minimum speed is necessary so that there is no tension in the string at the top of the circle but the rock stays in the same circular path?

Using the force balance expression at the top of the circle,

Gravitational Force + Tension force = Centrifugal force

m*g + T = m*v^2/R

Given that : T = 0

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v = \sqrt{g*R}

v = \sqrt{9.81*0.86}

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b) what is the maximum speed the rock can have so that the string does not break?

Here the  force balance at bottom of circle is represented by the illustration:

T = m*g + m*v^2/R

Given that:

maximum tension T = 45 N

maximum speed v = ??

mass  m = 0.75 kg

∴

45 - 0.75*9.81 = 0.75*\frac{v^2}{0.86} \\\\v^2 = 0.86*(45 - 0.75*9.81)/0.75 \\ v = \sqrt{0.86*(45 - 0.75*9.81)/0.75\\ maximum speed (v)= 6.57 m/sec.\\

c)

At what point in the vertical circle does this maximum value occur?

Maximum value of speed will occur at lowest point of vertical circle.

This is so because  at the lowest point; the tension in string will be maximum.

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Answer:

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1. mixing chocolate syrup into milk

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How should you behave while performing laboratory experiments?​
Brrunno [24]

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