Answer:
The expression of an equilibrium constant will given as:
![K_c=\frac{[NH_3]^2}{[N_2][H_2]^3}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BNH_3%5D%5E2%7D%7B%5BN_2%5D%5BH_2%5D%5E3%7D)
Explanation:
Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as 
K is the constant of a certain reaction when it is in equilibrium
The expression of an equilibrium constant will given as:
Answer:
The answer to your question is P2 = 170.9 torr
Explanation:
Data
Volume 1 = 12.1 l Volume 2 = 21.1 l
Temperature 1 = 241 °K Temperature 2 = 298°K
Pressure 1 = 546 torr Pressure 2 = ?
Process
To solve this problem use the combined gas law.
P1V1/T1 = P2V2/T2
-Solve for P2
P2 = T1V1T2 / T1V2
-Substitution
P2 = (241 x 12.1 x 298) / (241 x 21.1)
-Simplification
P2 = 868997.8 / 5085.1
-Result
P2 = 170.9 torr
Answer: Lithium
Explanation:
The ratio for the reaction of Li and water is the same, but there are more moles of water than lithium. Therefore, lithium is the limiting reactant.
Answer:
molecular weight (Mb) = 0.42 g/mol
Explanation:
mass sample (solute) (wb) = 58.125 g
mass sln = 750.0 g = mass solute + mass solvent
∴ solute (b) unknown nonelectrolyte compound
∴ solvent (a): water
⇒ mb = mol solute/Kg solvent (nb/wa)
boiling point:
- ΔT = K*mb = 100.220°C ≅ 373.22 K
∴ K water = 1.86 K.Kg/mol
⇒ Mb = ? (molecular weight) (wb/nb)
⇒ mb = ΔT / K
⇒ mb = (373.22 K) / (1.86 K.Kg/mol)
⇒ mb = 200.656 mol/Kg
∴ mass solvent = 750.0 g - 58.125 g = 691.875 g = 0.692 Kg
moles solute:
⇒ nb = (200.656 mol/Kg)*(0.692 Kg) = 138.83 mol solute
molecular weight:
⇒ Mb = (58.125 g)/(138.83 mol) = 0.42 g/mol
Answer:
1200 mL
Explanation:
Step 1:
Data obtained from the question. This includes the following:
Initial volume (V1) = 400 mL.
Initial pressure (P1) = 600 mmHg.
Final volume (V2) =..?
Final pressure (P2) = 200 mmHg
Step 2:
Determination of the final volume i.e the new volume of the gas.
Considering the question given, we understood that the temperature is constant. Therefore the gas is obeying Boyle's law. Using the Boyle's law equation, the new volume is obtained as follow:
P1V1 = P2V2
600 x 400 = 200 x V2
Divide both side by 200
V2 = (600 x 400) /200
V2 = 1200 mL
Therefore, the new volume of the gas is 1200 mL.
