How tall where the twin towers

Let m be an integer in the set {0,1,2,3,4,5,6,7,8, 9}, and consider the following problem: determine m by asking 3-way questions

kupik [55]

Answer:

Take any algorithm if that algorithm solves this problem it can be represented as a ternary decision tree. Therefore each question has at most three answers.

There are ten possible verdicts, the height of such kind of tree should satisfy

ℎ >= ⌈log3(10)⌉ = 3

Hence no such algorithm can ask less than three questions in the worst case.

---

b)

Each and every internal node represents a question asking whether m belongs to one of three possible subset of {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} or not

For example 0123|456|789 represented the questionDoes “m: belongs to {0, 1, 2, 3}, to {4, 5, 6}, or to {7, 8, 9}?"

Verdicts are placed in brackets "[ ]"

Explanation:

decision tree is attached below

5 0

3 years ago

Steam heated at constant pressure in a steam generator enters the first stage of a supercritical reheat cycle at 28 MPa, 5208C.

algol [13]

This question is incomplete, the complete question is;

Steam heated at constant pressure in a steam generator enters the first stage of a supercritical reheat cycle at 28 MPa, 520°C. Steam exiting the first-stage turbine at 6 MPa is reheated at constant pressure to 500°C. Each turbine stage has an isentropic efficiency of 78% while the pump has an isentropic efficiency of 82%. Saturated liquid exits the condenser that operates at constant pressure of 6 kPa.

Determine the quality of the steam exiting the second stage of the turbine and the thermal efficiency.

Answer:

- the quality of the steam exiting the second stage of the turbine is 0.9329

- the thermal efficiency is 36.05%

Explanation:

get the properties of steam at pressure p1 = 28 MPa and temperature T2 = 520°C .

Specific enthalpy h1= 3192.3 kJ/kg

Specific entropy s1 = 5.9566 kJ/kg.K

Process 1 to 2s is isentropic expansion process in the turbine

S1 = S2s

get the enthalpy at state 2s at pressure p2 = 6 MPa and S2s = 5.9566 kJ/kg.K

h2s = 2822.2 kJ/kg

get the enthalpy at state 2 using isentropic turbine efficiency of the turbine. nT1 = (h1 - h2) / (h1 - h2s)

0.78 = (3192.3 - h2) / (3192.3 - 2822.2)

h2 = 2903.6 kJ/kg

get the enthalpy at state 3 at pressure p2 = p3 = 6 MPa and T3 = 500°C

h3 = 3422.2 kJ/kg

s3 = 6.8803 kJ/kg.K

Process 3 to 4s is isentropic expansion process in the turbine

S3 = S4s

get the enthalpy at state 4s at pressure p4s = p4 = 6 kPa and S4s = 6.8803 kJ/kg.K

h4s = 2118.8 kJ/kg

get the enthalpy at state 4 using isentropic turbine efficiency of the turbine. nT2 = (h3 - h4) / (h3 - h4s)

0.78 = (3422.2 - h4) / ( 3422.2 - 2118.8 )

h4 = 2405.5 kJ/kg

get the properties at pressure, p5 = 6 kPa

h5 = hf

= 151.53 kJ/kg

v5 = Vf

= 0.0010064 m³/kg

get the enthalpy at state 6 using isentropic pump efficiency of the turbine, at

p6 = p1 = 28 MPa

np = v5( p6 - p5) / (h6 - h5)

0.82 = ((0.0010064)( 28000 - 6)) / (h6 - 151.53)

h6 = 185.89 kJ/kg

Now to find the quality of the steam at the exit of the second stage of the turbine

At stat4, p4 = 6kPa

h4f = 151.53 kJ/kg

h4fg = 2415.9 kJ/kg

h4 = h4f + x4h4fg

2405.5 = 151.53 + (x4 (2415.9))

x4 = 0.9329

the quality of the steam exiting the second stage of the turbine is 0.9329

Also to find the efficiency of the power plant, we use the following equation;

n = Wnet / Qin

= (Wt1 + Wt2 - Wp) / (Q61 + Q23)

= [(h1 - h2) + (h3 - h4) - (h6 - h5)] / [(h1 - h6) + (h3 - h2)]

[(3192.3 - 2903.6) + (3422.2 - 2405.5) - (185.89 - 151.53)] / [(3192.3 - 185.89) + (3422.2 - 2903.6)]

= 0.3605

n = 36.05%

therefore the thermal efficiency is 36.05%

3 0

3 years ago

Drivers education - Unit 3

melamori03 [73]

The following scenarios are pertinent to driving conditions that one may encounter. See the following rules of driving.

<h3>What do you do when the car is forced into the guardrail?</h3>

Best response:

I'll keep my hands on the wheel and slow down gradually.
The reason I keep my hands on the steering wheel is to avoid losing control.
This will allow me to slowly back away from the guard rail.
The next phase is to gradually return to the fast lane.
Slamming on the brakes at this moment would result in a collision with the car behind.

Scenario 2: When driving on a wet road and the car begins to slide

Best response:

It is not advised to accelerate.
Pumping the brakes is not recommended.
Even lightly depressing and holding down the brake pedal is not recommended.
The best thing to do is take one foot off the gas pedal.
There should be no severe twists at this time.

Scenario 3: When you are in slow traffic and you hear the siren of an ambulance behind

Best response:

The best thing to do at this moment is to go to the right side of the lane and come to a complete stop.
This helps to keep the patient in the ambulance alive.
It also provide a clear path for the ambulance.
Moving to the left is NOT recommended.
This will exacerbate the situation. If there is no place to park on the right shoulder of the road, it is preferable to stay in the lane.

Learn more about rules of driving. at;

brainly.com/question/8384066

#SPJ1

4 0

2 years ago

Consider an ADC with 6-bit resolution. When operating in unipolar mode, the ADC supports a 0 V-to-10 V range. What is the resolu

faltersainse [42]

Answer:

0.156 V

Explanation:

Analog to digital converter (ADC) is used to convert an analog signal into a digital signal.

Resolution of ADC means in how many parts the signal of interest can be divided.

The resolution can be found using

Q = Full scale Voltage range/2^M

Where the full scale voltage range is 10 V and M is the number of bits of the ADC.

Q = 10/2^6

Q = 10/64

Q = 0.156 V

Therefore, the smallest voltage difference that can be detectable by this ADC is 0.156 V

4 0

3 years ago

In this lab, your task is to configure the external vEthernet network adapter with the following IPv6 address: Prefix: 2620:14F0

OverLord2011 [107]

Here is the complete question

You work as the IT administrator for a small corporate network. You need to create a separate subnet to use for testing. The test subnet needs access to the rest of the network through a router, but it should not have any local access to production machines.

You have installed Windows Server 2016 on CorpRTR, which you plan to use to isolate the test segment from the rest of the network. You'll use traditional routing or NAT.

In this lab, your task is to add the necessary role and role services to meet the stated requirements. Do not add unnecessary role services.

Answer & Explanation:

Complete this lab as follows:

1.In the notification area, right-click the Network icon and select Open Network and Sharing Center.

2.On the left, select Change adapter settings.

3.Right-click the vEthernet (External)adapter and select Properties.

4.Select Internet Protocol Version 6 (TCP/IPv6).

5.Select Properties.

6.Select Use the following IPv6 address.

7.In the IPv6 address field, enter 2620:14F0:45EA:0001:192:168:0:10as the IPv6 address.

8.In the Subnet prefix length field, enter 64.

9.Click OK.

10.Click Close.

11.In the Search the web and Windows field, enter cmd.

12.Under Best match, right-click Command Prompt and select Run as Administrator.

13.At the command prompt, type ipconfig /all and press Enter to view the IPv6 address.

4 0

4 years ago