Has anyone has the answers for Physical Education # 12 cross word and the word search?
2 answers:
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Answer:
Option D: 1.5in in front of the target
Explanation:
The object distance is .
Because the surface is flat, the radius of curvature is infinity .
The incident index is and the transmitted index is
.
The single interface equation is
Substituting the quantities given in the problem,
The image distance is then
Therefore, the coin falls in front of the target
They were going at a velocity 4.07m/s
<u>Explanation:</u>
Distance s =5 m
initial velocity u= 0.8 m/s
Acceleration a =1.6m/s2
We have to calculate the velocity with which they were going afterwards i.e final velocity.
Use the equation of motion
They were going with a velocity 4.07 m/s afterwards.