What is the value of ΔVBA=VB−VA if the charge on the plates is 1.00 x 10-9 C, the area of the plates is 2.00 m2 and the distanc
e between points A and B is 5.00 cm? ϵ0=8.85×10−12 C2N⋅m2
1 answer:
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Answer:
Calculating Coefficient of friction is 0.229.
Force is 4.5 N that keep the block moving at a constant speed.
Explanation:
We know that speed expression is as .
Where, is initial speed, V is final speed, ∆s displacement and a acceleration.
Given that,
=3 m/s, V = 0 m/s, and ∆s = 2 m
Substitute the values in the above formula,
0 = 9 - 4a
4a = 9
is the acceleration.
Calculating Coefficient of friction:
Compare the above equation
Cancel "m" common term in both L.H.S and R.H.S
Hence coefficient of friction is 0.229.
calculating force:
F = 4.5 N
Therefore, the force would be <u>4.5 N</u> to keep the block moving at a constant speed across the floor.
The frequency of the wave is 6800 Hz
<u>Explanation:</u>
Given:
Wave number, n = 20
Speed of light, v = 340 m/s
Frequency, f = ?
we know:
wave number =
Therefore, the frequency of the wave is 6800 Hz