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Sophie [7]
2 years ago
7

How many atoms are in 0.75 moles of CH4?

Chemistry
1 answer:
Anastasy [175]2 years ago
6 0

Answer:

Explanation:

Thus, if we have 6.022 × 10 23 O atoms, we say we have 1 mol of O atoms. If we have 2 mol of Na atoms, we have 2 × (6.022 × 10 23) Na atoms, or 1.2044 × 10 24 Na atoms. Similarly, if we have 0.5 mol of benzene (C 6H 6) molecules, we have 0.5 × (6.022 × 10 23) C 6H 6 molecules, or 3.011 × 10 23 C 6H 6 molecules.

For example the atomic mass of methane (CH4)is 12 amu for the carbon plus 4 x 1 amu for the four hydrogens, for a total of 16 amu. Therefore the molar mass of methane is 16g. We say that one mole of methane has a mass of 16 g, and that there are 6.022 x 1023 atoms in that mass of methane.

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Details about outer ear
Verdich [7]
Outer ear is the is external part of the ear, consists of the auricle ( also pinna), and the ear canal. It gathers sound energy and focuses it on the ear drum.  
7 0
3 years ago
HELP PLSSSSS!!
11Alexandr11 [23.1K]

Answer:

68133080.02 g

Explanation:

I believe that the question is to find the mass of air in the room and not the molar mass of air since the molar mass of air was already given in the question as 28.97 g/mol.

Now, if 1 mole of a gas occupies 22.4 L

x moles of air occupies 52,681,428.8 Liters

x = 1 * 52,681,428.8 /22.4

x = 2351849.5 moles of air

Now, number of moles = mass/ molar mass

but molar mass = 28.97 g/mol

2351849.5 = mass/28.97

mass = 2351849.5 * 28.97

mass = 68133080.02 g

7 0
3 years ago
Determine the volume of atmospheric air (at 14 lb/in.^2) needed to fill your bike tires (assuming it holds 500 mL of air) to the
Fiesta28 [93]

Boyle Law says “the pressure of fixed amount of ideal gas which is at constant temperature is inversely proportional to its volume".<span>

P = 1/V

<span>Where, P is pressure of the ideal gas and V is volume of the ideal gas.</span>

<span>For two situations, this law can be added as;
P</span>₁V₁ = P₂V₂<span>

</span><span>14 lb/in² x V₁ = 70 lb/in² x 500 mL</span><span>
                 </span><span>V₁ = 2500 mL</span><span>

Hence, the needed volume of atmospheric air = 2500 mL

<span>Here, we made two </span>assumptions. They are,
1. The atmospheric air acts as ideal gas.
2. Temperature is a constant.

<span>We didn't convert the units to SI units since converting volume and pressure are products of two numbers, they will cut off. </span></span></span>

3 0
3 years ago
Given the molecular formula, C9H13N, the correct empirical formula<br> is
Lesechka [4]

Answer:

C9H13N

Explanation:

Since there is no common factor besides 1, the formula is already the empirical formula for this compound.

7 0
2 years ago
Which of the following is necessarily characterized by a covalent linkage?a. Base-pairing interactionb. Disulfide bondc. Hydroge
mr_godi [17]

Answer:

b. Disulfide bond

Explanation:

Covalent linkage or bonding is a type of bond in which electrons are shared between atoms in a compound or molecule. Each atom contributes to the shared electron.

This is the case of disulfide bonding i.e. S-S, in which two thiol groups (-SH) share electrons with one another. The process of oxidation between two cysteine (amino acid) molecules forms this bond. Hence, Disulfide bond is characterized by a covalent linkage.

6 0
3 years ago
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