In this problem, we are given with the resultant velocity of the swimmer considering the current is running 0.91 m/s that is equal to 1.1 m/s2. In this case, using v = d/t, t = 3000m / 1.1 m/s equal to 2727.27 seconds equal to 45.45 hours. The distance downstream is equal to 2727.27 seconds * 0.91 m/s equal to 2481.82 meters.
Answer:
ΔK = 24 joules.
Explanation:
Δ
Work done on the object
Work is equal to the dot product of force supplied and the displacement of the object.
* Δ
Δ can be found by subtracting the vectors (7.0, -8.0) and (11.0, -5.0), which is written as Δ = (11.0 - 7.0, -5.0 - -8.0) which equals (4.0, 3.0).
This gives us
* 
= 
= 
J
Answer:
14.5 hours
Explanation:
The relationship between speed, time and distance for a uniform motion is
where
v is the speed
d is the distance
t is the time taken
Here we know:
v = 24.0 m/s is the average speed
is the distance
Solving the equation, we find the time taken:
And since
1 hour = 3600 s
The time in hours is
For a current loop with a radius 20 cm and current 2 A is in a uniform magnetic field of 0.5 T, largest potential energy difference is mathematically given as
du=0.2512J
<h3>What is the largest potential energy difference (in Joules) you can find between two orientations?</h3>
Generally, the equation for the initial velocity is mathematically given as
v0=-iAB
Therefore
-2*\pi(0.2)(0.5))
v0=-0.1256J
for 180
theta=0180=-iABcos180
V180=0.1256J
Therefore
du=v180-v0
0.1258-(-0.1256
du=0.2512J
In conclusion, potential energy
du=0.2512J
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