(a)
KE = m v^2 / 2 = (1200 kg)(20 m/s)^2 / 2 = 240,000 J
(b)
The energy is entirely dissipated by the force of friction in the brake system.
(c)
W = delta KE = KEf - KEi = (0 - 240,000) J = -240,000 J
(d)
Fd = delta KE
F = (delta KE) / d = (-240,000 J) / (50 m) = -4800 N
The magnitude of the friction force is 4800 N.
Answer:
The correct option is;
c. 22.6
Explanation:
The given parameters are;
The hypotenuse of the vector = 32
The angle of the vector = 45°
Therefore, the vector component in the y-axis is given as follows;

Substituting the values from the question gives;

The vector component in the y-axis,
, is approximately 22.6.
Answer:
the correct representation of the trough is b
Awnser: 600 meters per hour
Step by step explication:
Covert 14 minutes to a fraction of an hour by dividing it by 60, because 60 is how many minutes in an hour and we need to convert it to a decimals. Then divide the distance, 150 meters by the fraction of an hour, .25 to abstain the velocity (speed) of 600 meters per hour.