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3 years ago

How do the lungs and heart transport oxygen in the cardio respiratory system

2 answers:

7 0

The lungs hold air that is taken in. Oxygen gas noticeable all around moves into the blood. The heart pumps to transports this oxygenated blood to cells in the body that need it to deliver vitality.

xz_007 [3.2K]3 years ago

5 0

The lungs hold air that is breathed in.Oxygen gas in the air moves intothe blood. The heart pumps to transports this oxygenated bloodto cells in the body that need it toproduce energy.

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50 point!! Will mark brainliest!! (Please help)

jok3333 [9.3K]

What is the variable?

~the price is the variable.

What happens to demand?

~It'll go down. Since the price of snow blowers will increase then the quantity demanded will go down.

Hope this helps- have a good day bro cya)

4 0

2 years ago

Read 2 more answers

A plane designed for vertical takeoff has a mass of 8.0 × 10³ kg. Find the net work done by all forces on the plane as it accele

artcher [175]

Answer:

the net work done after starting from rest is = 2.4 × 10⁵ J

Explanation:

Work: Work can be defined as the product of force and distance. The fundamental unit of work is Joules (J), The unit of Energy is Joules (J), as such Energy and work are interchangeable during calculation, This is illustrated below

E = W = 1/2mv².......................... Equation 1

Where m = mass of the plane, v = velocity of the plane, E = Energy, W = work done.

v² = u² + 2as ................................. Equation 2.

Where v = final velocity of the plane, u = initial velocity of the plane, a = acceleration of the plane, distance of the plane.

Given: a = 1.0 m/s², s = 30 m, u = 0 m/s (at rest)

Substituting these values into equation 2

v² = 0² +2×1×30

v² = 60

v = √60

v = 7.75 m/s

Also given: m = 8.0 × 10³ kg, and v = 7.75 m/s

Substituting these values into equation 1,

W = 1/2(8.0×10³)(7.75)²

W = (4.0×10³)(60)

W = 240 × 10³ J

W = 2.4 × 10⁵ J

Therefore the net work done after starting from rest is = 2.4 × 10⁵ J

4 0

3 years ago

A +2.00nc point charge is at the origin, and a second -5.00nc point charge is on the x-axis at x = 0.800m find the magnitude of

Damm [24]

You have to reduce 2.00 an5.00 I order to use the×that=0.800

3 0

2 years ago

In a cold winters day, if you left a cup of water sitting outside, it could freeze. Heat is transferred out of the water. Descri

Agata [3.3K]

If you were to sit a hot cup of water out side it would frezze faster

4 0

3 years ago

What is the kinetic energy of an object with a mass of 50kg and is and it is traveling at a rate of 60m/s.

liq [111]

Answer:

90,000 J

Explanation:

Kinetic energy can be found using the following formula.

$KE=\frac{1}{2}mv^2$

where m is the mass in kilograms and v is the velocity in m/s.

We know the object has a mass of 50 kilograms. We also know it is a traveling at a rate of 60 m/s. Velocity is the speed of something, so the velocity of the object is 60 m/s.

m=50

v=60

Substitute these values into the formula.

$KE=\frac{1}{2}*50*60^2$