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Nuetrik [128]
3 years ago
8

How are elements in the same group in the periodic table alike

Chemistry
2 answers:
kolbaska11 [484]3 years ago
6 0
C or D sorry if neither
ale4655 [162]3 years ago
4 0

Answer:

D. They have similar chemical properties

Explanation:

That's because they have the same number of electrons in the outer orbital

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A defibrillator delivers about 300 joules per shock calculate the number of calories
Tanya [424]

Answer:- 71.7 calories

Solution:- it is a unit conversion problem where we need to convert joules into calories.

The unit conversion for these energy units is:

1 calorie = 4.184 joule

The given energy is 300 joules and has to be converted to calories. We will show the set up using dimensional analysis.

300joules(\frac{1calorie}{4.184joules})

= 71.7 calories

So, the energy in calories is 71.7.


4 0
3 years ago
What is an example of equilibrium?
frez [133]

A good example of equilibrium would be the mixing of oil and water in a closed container.

<h3>What is chemical equilibrium?</h3>

Chemical equilibrium is a condition in which the concentrations of components of a chemical reaction remain unchanged and have no tendency to change.

Of all the options, the only one where the concentrations of the component reactants cannot change is a mixture containing oil and water in a closed container.

Oil and water are immiscible and thus, their concentrations remain constant.

More on chemical equilibrium can be found here: brainly.com/question/4289021

#SPJ1

5 0
2 years ago
Which of the following solutes has the greatest effect on the colligative properties for a given mass of pure water? Explain.
Strike441 [17]

Answer:

Option a.

0.01 mol of CaCl₂ will have the greatest effect on the colligative properties, because it has the biggest i

Explanation:

To determine which of the solute is going to have a greatest effect on colligative properties we have to consider the Van't Hoff factor (i)

These are the colligative properties:

ΔP = P° . Xm . i  →  Lowering vapor pressure

ΔT = Kb . m . i  → Boiling point elevation

ΔT = Kf . m . i  →  Freezing point depression

π = M . R . T  →  Osmotic pressure

Van't Hoff factor are the numbers of ions dissolved in the solution. For nonelectrolytes, the i values 1.

CaCl₂ and KNO₃ are two ionic solutes. They dissociate as this:

CaCl₂  → Ca²⁺ + 2Cl⁻

We have 1 mol of Ca²⁺ and 2 chlorides, so 3 moles of ions → i = 3

KNO₃ → K⁺ + NO₃⁻

We have 1 mol of K⁺ and 1 mol of nitrate, so 2 moles of ions → i = 2

Option a, is the best.

8 0
3 years ago
An electrolytic cell is based upon a nonspontaneous reaction; the Eocell for the reaction is _____.
Likurg_2 [28]

In an electrochemical cell in which the oxidation reaction is nonspontaneous  the oxidation will not occur spontaneously at the anode and the reduction will not be spontaneous at the cathode.  And according to the law for the calculation of the voltage potential of the electrochemical cell (Ecell):

Ecell = Eox. - Ere.  where (Eox. is the potential of the oxidation at the anode and Ere. is the potential of the reduction at the cathode). The standard potential for an electrolytic cell is negative, because of the Ere. which is greater than Eox.

The answer is : less than zero.

6 0
3 years ago
High-density polyethylene may be flourinated by inducing the random substitution of Flourine atoms for hydrogen. (a) Determine t
Lemur [1.5K]

Answer:

Concentration of Flourine = 24.756%

Explanation:

Given that :

High-density polyethylene may be flourinated by inducing the random substitution of Flourine atoms for hydrogen.

the objective is to determine he concentration of Flourine (in wt%) that must be added if this substitution occurs for 12% of all the original hydrogen atoms.

At standard conditions , the atomic weight of the these compounds are as follows:

Carbon = 12.01 g/mol

Chlorine = 35.45 g/mol

Fluorine = 19.00 g/mol

Hydrogen = 1.008 g/mol

Oxygen = 16.00 g/mol

The chemical formula for polyethylene = (CH₂ - CH₂)ₙ

Therefore, for two carbons, there will be 4 hydrogens;

i.e

(CH₂ - CH₂)₂

( C₂H₄ - C₂H₄ )

Suppose the number of original hydrogen = 4moles

number of moles of Flourine F = 12% of 4

= 0.12 × 4

= 0.48 mol

∴ the number of remaining moles of Hydrogen is:

= 4 - 0.48

= 3.52 moles

number of moles of Carbon = 2 moles

∴ the mass of flourine F = number of moles of F × molar mass of F

= 0.48 × 19

= 9.12

The total mass of the compound now is = (0.48 × 19 ) + (3.52 × 1) + (2× 12)

= 9.12 + 3.52 + 24

= 36.64

Concentration of Flourine = (mass of flourine/total mass) × 100

Concentration of Flourine = (9.12/36.84 ) × 100

Concentration of Flourine = 0.24756 × 100

Concentration of Flourine = 24.756%

3 0
3 years ago
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