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Burka [1]
2 years ago
6

A linebacker runs at 3 m/s and collides with a running back running towards him at 3.2

Physics
1 answer:
Anit [1.1K]2 years ago
3 0

Answer:b

Explanation:

im in fifth grade so i guessd. gl tho heh.

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Convert Rev/min to rad/s x 2pie/60?<br><br> Anyone knows this please?
defon

Answer:

Thus, \frac{1 rev}{min} =\frac{2\pi}{60} rad/s

Explanation:

The angular speed is defined as the rate of change of angular velocity.

Its SI unit is rad/s and other units are rev/min or rev/s.

\frac{1 rev}{min } = \frac{1 rev}{60 sec}\\\\1 rev = 2\pi rad\\\\So\\\\\frac{1 rev}{min} = \frac{2\pi}{60} rad/s

8 0
3 years ago
in a football game, the kicker kicks a football a horizontal distance of 43 yards if the ball lands 3.9 seconds later, what is t
erica [24]

Answer:

10s

Explanation:

7 0
3 years ago
A heavy rock is shot upward from the edge of a vertical cliff. It leaves the edge of the cliff with an initial velocity of 12 m/
jenyasd209 [6]

Answer:

The height of the building is 88.63 m.

Explanation:

Given;

initial component of vertical velocity, v_i = 12 m/s sin 26° = 5.26 m/s

initial horizontal component of the velocity, u_i = 12 m/s cos 26° =10.786 m/s

horizontal distance traveled by the rock, x = 40.4 m

time of flight is calculated as;

x = u_i t

t = x / u_i

t = 40.4 / 10.786

t = 3.75 s

Determine the final vertical velocity of the ball;

v_f = v_i + gt\\\\v_f = 5.26 + (9.8 *3.75)\\\\v_f = 42.01 \ m/s

Determine the height of the rock;

v_f^2 = v_i^2 + 2gh\\\\h = \frac{v_f^2 - v_i^2}{2g}\\\\ h = \frac{(42.01)^2 - (5.26)^2}{2*9.8}\\\\h = 88.63 \ m

Therefore, the height of the building is 88.63 m.

5 0
3 years ago
According to the law of conservation of energy, how are potential energy and kinetic energy related?
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Your answer should be A, because every reaction has an equal opposite reaction
6 0
2 years ago
Explain why a battery causes charge to flow spontaneously when the battery is inserted in a circuit
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Batteries supply electrons to the circuit by releasing negatively charged atoms or ions. These ions are produced by the batteries through a chemical reaction that spontaneously occurs within the battery. So the negative end of the battery pushes the ions towards the positive end of the circuit with the help of the voltage. This is why eventually, batteries "run out" when the electrode is used up and the chemical reaction can no longer continue.
3 0
3 years ago
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