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I realllyy need help with this, I don't know how to draw it! Please help me, If you do, I'll be sure to give you prayers for the good help you gave me, & Pay you back in return! you'll be a livesaver if you send me a picture! :)
1 answer:
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Answer:
His resulting velocity will be 0.187 m/s backwards.
Explanation:
Given:
Mass of the man is,
Mass of the ball is,
Initial velocity of the man is,
Initial velocity of the ball is,
Final velocity of the ball is,
Final velocity of the man is,
In order to solve this problem, we apply law of conservation of momentum.
It states that sum of initial momentum is equal to the sum of final momentum.
Momentum is the product of mass and velocity.
Initial momentum = Initial momentum of man and ball
Initial momentum =
Final momentum = Final momentum of man and ball
Final momentum =
Now, initial momentum = final momentum
The negative sign implies backward motion of the man.
Therefore, his resulting velocity is 0.187 m/s backwards.
Answer:
The package was released at a height of 1015.296 meters.
Explanation:
The package is dropped at an initial velocity different of zero, decelerated and later accelerated by gravity. Let assume that final height is equal to zero, the final height is given by the following equation of motion:
Where:
- Initial velocity, measured in meters per second.
- Final height, measured in meters.
- Initial height, measured in meters.
- Time, measured in seconds.
- Gravitational constant, measured in meters per square second.
(Positive sign - Package is moving upward, Negative sign - Package is moving downward)
The initial height is now cleared:
Given that ,
,
and
, the final height of the package is:
The package was released at a height of 1015.296 meters.