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Answer:
(a) 
(b) 
Explanation:
Given:
*p = charge on proton = 
*e = magnitude of charge on an electron =
*r = distance between the proton and the electron in the Rutherford's atom = 
Part (a):
Since two unlike charges attract each other.
According to Coulomb's law:
Hence, the attractive electrostatic force of attraction acting between an electron and a proton of Rutherford's atom is 
.
Part (b):
Potential energy between two charges separated by a distance r is given by:
So, the potential energy between the electron and the proton of the Rutherford's atom is given by:
Hence, the electrostatic potential energy of the atom is .
Hey user
The energy E in joules (J) is equal to the voltage V in volts (V), times the electrical charge Q in coulombs (C):
E(J) = V(V) ×<span> Q</span>(C)
So
joule = volt × coulomb
or
J = V × C
Example
What is the energy in joules that is consumed in an electrical circuit with voltage supply of 15V and charge flow of 4 coulombs?
E = 15V × 4C = 60J
Answer:
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Explanation:
The Nucleus: The Center of an Atom. The nucleus, that dense central core of the atom, contains both protons and neutrons. Electrons are outside the nucleus in energy levels.
C.-2 miles per hour per second
Explanation;
Acceleration = change in velocity / time
Acceleration = (final velocity - initial velocity )/time
Acceleration = (v - u)/t
Given: u = 20 miles per hour, v = 10 miles per hour
t = 5 seconds
Acceleration = (10 - 20)/5
Acceleration = -10/5
Acceleration = -2 miles per hour per second
