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Bingel [31]
4 years ago
11

A homogeneous mixture has the same composition throughout. a. True b. False

Chemistry
1 answer:
Flura [38]4 years ago
3 0
The answer is true. I get those mixed up to
You might be interested in
A strong acid OR base is one that:
kupik [55]

Answer: completely (100%) dissociates, producing a significant amount of H+ and OH- ions in solution, making it conduct electricity well.

Explanation:

A strong acid is one that ionizes or dissociate completely in water to yield its hydrogen ion (H+) as the only positively charged ion.

For example: Hydrochloric acid (HCl) dissociates completely in water to give hydrogen ion and chlorine ion

HCl(aq) --> H+(aq) + Cl-(aq)

A strong base, on the other hand, dissociates completely in water to yield an hydroxyl ion (OH-) as the only negatively charged ion. A good example is Sodium hydroxide NaOH

NaOH (aq) --> Na+(aq) + OH-(aq)

And since mobile and charged ions help transmit electric current, a strong acid or base produces significant amount of H+ and OH- ions that conduct electricity well.

6 0
4 years ago
2. a) Balance the equation: _NaOH + _Cl2 → NaOCl + NaCl + H2O
Gre4nikov [31]

Answer: 2NaOH+Cl₂=NaClO+NaCl+H₂O

Explanation:

3 0
4 years ago
A few substances are arranged in the increasing order of ‘forces of attraction’ between their particles. Which one of the follow
gavmur [86]

Answer:

A.

Explanation:

PO WATER,AIR,WIND

7 0
3 years ago
How many molecules are there in 0.75 mol NH3
vitfil [10]
3 *0.75 = 2.25 mol that’s is ur answer for this question
4 0
3 years ago
The following reaction was performed in a sealed vessel at 791 ∘C : H2(g)+I2(g)⇌2HI(g) Initially, only H2 and I2 were present at
OlgaM077 [116]

Answer:

4.31 × 10²

Explanation:

Equation of the reaction;

H_{2(g)} + I_{2(g)}     ⇌     2HI_{(g)

The ICE Table is shown as follows:

                            H_{2(g)}         +         I_{2(g)}        ⇌     2HI_{(g)

Initial                    3.10                     2.50                  0      

Change                 - x                       -x                     + 2x      

Equilibrium        (3.10 - x)                0.0800              2x

From I_{2(g)}   ;

We can see that 2.50 - x = 0.0800

So; we can solve for x;

x = 2.50 - 0.0800

x = 2.42

H_{2(g)}  which = (3.10 -x) will be :

= 3.10 - 2.42

= 0.68

2HI_{(g) = 2x

= 2 (2.42)

= 4.84

K_c = \frac{[HI]^2}{[H_2][I_2]}

K_c = \frac{(4.84)^2}{(0.68)(0.0800)}

K_c =\frac{23.4256}{0.0544}

K_c = 430.62

K_c ≅ 431

K_c = 4.31 × 10²

6 0
3 years ago
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