The final volume of the unknown gas is 787.5 ml
Given:
volume of unknown gas = 450.0 mL
initial pressure of unknown gas = 0.07 atm
final pressure of unknown gas = 0.04 atm
To Find:
final volume of the unknown gas
Solution:
Substituting these values into Boyle’s law, we get
P1V1 = P2V2
(0.07)(450) = (0.04)V2
V2 = (0.07)(450)/(0.04)
V2 = 787.5
So, final volume of the unknown gas is 787.5 ml
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That would be ionic lattice.
Explanation:
nah biaar seneng, tuh ku jawab:c
Answer:
ΔH = - 2020.57 kJ/mol
Explanation:
Given that :
mass of propanol = 1.685 g
the molar molar mass = 60 g/mol
Thus; the number of moles = mass/molar mass
= 1.685 g/60 g/mol
= 0.028 g/mol
However ;
ΔH = heat capacity C × Δ T
Given that:
The temperature increases from 298.00 K to 302.16 K.
Then ;
Δ T = 302.16 K - 298.00 K
Δ T = 4.16 K
heat capacity C = 13.60 kJ/K
∴
ΔH = 13.60 kJ/K × 4.16 K
ΔH = 56.576 kJ
The equation of the given reaction can be represented as :

Thus for 0.028 mol of heat liberated; ΔH = 56.576 kJ
For 1 mole of heat liberated now:
ΔH = 56.576 kJ/0.028 mol
ΔH = 2020.57 kJ/mol
SInce , Heat is liberated, the reaction undergoes an exothermic reaction thus;
ΔH = - 2020.57 kJ/mol
The strength of an acid increases if the stability of conjugate base increases
The stability of a conjugate base increases with the presence of electron with drawing group (electronegative group)
Thus more the electronegativity of an atom attached to a carboxylic acid higher the strength of acid
In these examples CH3CH2CH2CF2CH2COOH contains to electronegative flourine atoms which stabilizes the conjugate base hence this will be the strongest acid among the given acids