Answer : The value of Ka for acetic acid is, 
Explanation :
The chemical formula of acetic acid is,
.
The chemical equilibrium reaction will be:

Given:
pH = 2.96
First we have to calculate the concentration of hydrogen ion.
![pH=-\log [H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D)
![2.96=-\log [H^+]](https://tex.z-dn.net/?f=2.96%3D-%5Clog%20%5BH%5E%2B%5D)
![[H^+]=1.096\times 10^{-3}M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D1.096%5Ctimes%2010%5E%7B-3%7DM)
That means,
![[H^+]=[CH_3COO^-]=1.096\times 10^{-3}M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D%5BCH_3COO%5E-%5D%3D1.096%5Ctimes%2010%5E%7B-3%7DM)
![[CH_3COOH]=0.0602-(1.096\times 10^{-3})=0.0591M](https://tex.z-dn.net/?f=%5BCH_3COOH%5D%3D0.0602-%281.096%5Ctimes%2010%5E%7B-3%7D%29%3D0.0591M)
The expression for reaction is:
![K_a=\frac{[CH_3COO^-][H^+]}{[CH_3COOH]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BCH_3COO%5E-%5D%5BH%5E%2B%5D%7D%7B%5BCH_3COOH%5D%7D)


Thus, the value of Ka for acetic acid is, 
Answer:
In engineering and science the common stand is two places.
For example if you get a calculation of 4.567 round up and give the result of 4.57
Answer:
In the Lewis structure of P4 there are 6 bonding pairs and 4 lone pairs of electrons.
Explanation:
The structure of tetrahedral molecule of P4 is provided below.
Each phosphorus atom has 5 valence electrons out of which 3 electrons involve in bonding and the rest 2 electrons exist as a lone pair that does not involve in bonding.Hence each phosphorus atom has one lone pair.In P4 molecule there are phosphorus atoms and hence 4 lone pairs in total.
As you can see in the figure, each phosphorus atom is bonded to the other three atoms.A bond is formed when two atoms share one electron each and the pair is called bonding pair.
From the figure we can see that there are 6 bonds in total.Each bond consist of one bonding pair of electrons and hence in total there are 6 bonding pairs of electrons.
Hence in a P4 molecule there are six bonding pairs and 4 lone pairs of electrons.
Answer:
3m/s
Explanation:
Data obtained from the question include:
Initial speed (s1) = 4 m/s
Final speed (S2) = 7m/s
Change in speed (ΔS)
ΔS = s2 — s1
ΔS = 7 — 4
ΔS = 3m/s
Therefore, the change in speed is 3m/s
Answer:-
The reaction of 2-bromopropane reacts with sodium iodide in acetone is an example of Sn2 reaction.
The I - attacks from backside to give the transition state for both.
If we compare the transition state for cyclobromopropane 2-bromopropane then we see in case of cyclobromopropane transition state, one of the H is very close to the incoming I -.
This results in steric strain and less stability of the transition state. Hence 2-bromopropane reacts with sodium iodide in acetone over 104 times faster than bromocyclopropane.