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Fantom [35]
4 years ago
10

Most geologists accept radiometric dating techniques as valid because

Physics
2 answers:
Rus_ich [418]4 years ago
7 0

Most geologists accept radiometric dating techniques as valid because radioactive elements decay at a constant and measurable rate.

Answer: Option C

<u>Explanation:</u>

Scientists prefer radioactive dating to carbon dating because it is more accurate in measuring.  The analysis depends upon the radioactive decay of radioactive isotopes of any matter in a given rock or soil.

The parent atoms and daughter atoms are compared while studying, and hence age can be calculated easily. Radioactive decay depends upon the given half-life of the atom, which is a constant and is known. So, it would be very easy to calculate the number of progeny atoms and parent atoms and find out their age.

DanielleElmas [232]4 years ago
6 0

The correct answer is C. Radioactive elements decay at a constant and measurable rate.

Explanation:

Radiometric dating is a technique used by geologists to determine how old some materials or elements are, for example, rocks or fossils. This technique focuses on measuring the decay of radioactive elements in the materials. This is possible because most materials contain traces of radioactive elements and decay at a constant rate over time. which has been widely studied and measured. Due to this, a certain rate of decay is equivalent to a specific number of years and through this, geologists can now the age of rocks and other elements. Thus, this technique is accepted as valid because "radioactive elements decay at a constant and measurable rate".

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A parallel-plate air capacitor is made from two plates 0.190 m square, spaced 0.770 cm apart. It is connected to a 120 V battery
Naddik [55]

Answer:

aaksj

Explanation:

a) the capacitance is given of a plate capacitor is given by:

C = \epsilon_0*(A/d)

Where \epsilon_0 is a constant that represents the insulator between the plates (in this case air, \epsilon_0 = 8.84*10^(-12) F/m), A is the plate's area and d is the distance between the plates. So we have:

The plates are squares so their area is given by:

A = L^2 = 0.19^2 = 0.0361 m^2

C = 8.84*10^(-12)*(0.0361/0.0077) = 8.84*10^(-12) * 4.6883 = 41.444*10^(-12) F

b) The charge on the plates is given by the product of the capacitance by the voltage applied to it:

Q = C*V = 41.444*10^(-12)*120 = 4973.361 * 10^(-12) C = 4.973 * 10^(-9) C

c) The electric field on a capacitor is given by:

E = Q/(A*\epsilon_0) = [4.973*10^(-9)]/[0.0361*8.84*10^(-12)]

E = [4.973*10^(-9)]/[0.3191*10^(-12)] = 15.58*10^(3) V/m

d) The energy stored on the capacitor is given by:

W = 0.5*(C*V^2) = 0.5*[41.444*10^(-12) * (120)^2] = 298396.8*10^(-12) = 0.298 * 10 ^6 J

6 0
3 years ago
Read 2 more answers
What is the difference between first aid and first aid kit
Archy [21]

Answer:

One has the word kit and the other doesn't

7 0
2 years ago
Why do we see only one side of the moon from earth?
Anna11 [10]
<span>We see only one side of the moon from earth because the moons period of rotation and revolution are equal. The moon rotates around the Earth at the exact speed as it rotates around its won axis (revolution). The result is: the same side of the moon is facing the Earth. If the moon doesn't rotate on it's axis we on the Earth would see all of the sides of the Moon.</span>
3 0
3 years ago
Read 2 more answers
Starting from Newton’s law of universal gravitation, show how to find the speed of the moon in its orbit from the earth-moon dis
WARRIOR [948]

Answer: 1010.92 m/s

Explanation:

According to Newton's law of universal gravitation:

F=G\frac{Mm}{r^{2}} (1)

Where:

F is the gravitational force between Earth and Moon

G=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}} is the Gravitational Constant  

M=5.972(10)^{24} kg is the mass of the Earth

m=7.349(10)^{22} kg is the mass of the Moon

r=3.9(10)^{8} m is the distance between the Earth and Moon

Asuming the orbit of the Moon around the Earth is a circular orbit, the Earth exerts a centripetal force on the moon, which is equal to F:

F=m.a_{C} (2)

Where a_{C} is the centripetal acceleration given by:

a_{C}=\frac{V^{2}}{r} (3)  

Being V the orbital velocity of the moon

Making (1)=(2):

m.a_{C}=G\frac{Mm}{r^{2}} (4)

Simplifying:

a_{C}=G\frac{M}{r^{2}} (5)

Making (5)=(3):

\frac{V^{2}}{r}=G\frac{M}{r^{2}} (6)  

Finding V:

V=\sqrt{\frac{GM}{r}} (7)

V=\sqrt{\frac{(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(5.972(10)^{24} kg)}{3.9(10)^{8} m}} (8)

Finally:

V=1010.92 m/s

5 0
3 years ago
What is the monthly cost of using a 750 W refrigerator that runs for 8 hours every day, if the cost per kWh is $0.23?
disa [49]

Answer:

Assuming there are 28 days in each month,

750W = 0.75kW

Cost of electric bill = 0.75 × 8 × 28 × $0.23

                               = $38.64

8 0
2 years ago
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