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Fantom [35]
3 years ago
10

Most geologists accept radiometric dating techniques as valid because

Physics
2 answers:
Rus_ich [418]3 years ago
7 0

Most geologists accept radiometric dating techniques as valid because radioactive elements decay at a constant and measurable rate.

Answer: Option C

<u>Explanation:</u>

Scientists prefer radioactive dating to carbon dating because it is more accurate in measuring.  The analysis depends upon the radioactive decay of radioactive isotopes of any matter in a given rock or soil.

The parent atoms and daughter atoms are compared while studying, and hence age can be calculated easily. Radioactive decay depends upon the given half-life of the atom, which is a constant and is known. So, it would be very easy to calculate the number of progeny atoms and parent atoms and find out their age.

DanielleElmas [232]3 years ago
6 0

The correct answer is C. Radioactive elements decay at a constant and measurable rate.

Explanation:

Radiometric dating is a technique used by geologists to determine how old some materials or elements are, for example, rocks or fossils. This technique focuses on measuring the decay of radioactive elements in the materials. This is possible because most materials contain traces of radioactive elements and decay at a constant rate over time. which has been widely studied and measured. Due to this, a certain rate of decay is equivalent to a specific number of years and through this, geologists can now the age of rocks and other elements. Thus, this technique is accepted as valid because "radioactive elements decay at a constant and measurable rate".

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You could use an elevator or stairs to lift a box to the tenth floor. Which has greater energy? Why?
love history [14]
Stairs because every step u take u use energy and the more steps the more energy
6 0
3 years ago
While watching a small fireworks display from a building 204 feet tall, you observe a rocket that travels from ground to eye lev
faltersainse [42]
204 ft = 62.2 m
We know that the initial velocity of the rocket was 0, we can find its acceleration using:
s = ut + 1/2 at²
62.2 = 0.5a(6)²
a = 3.46 m/s²
Now, the final velocity of the rocket:
v = u + at
v = 3.46 x 6
v = 20.76 m/s = 68.1 ft/s
4 0
3 years ago
In the far future, astronauts travel to the planet Saturn and land on Mimas, one of its 62 moons. Mimas is small compared with t
OverLord2011 [107]

Answer:

a) h = 13,205.4 m

b)  r_f = 2.12 106 m

c)        e% = 0.68%

Explanation:

a) This is an exercise we are asked to use energy conservation,

Starting point. On the surface of Mimas

        Em₀ = K = ½ m v²

Final point. Where the ball stops

       Em_{f} = U = m g h

        Em₀ = Em_{f}

        ½ m v² = m g h

         h = ½ v² / g

let's calculate

         h = ½ 41² / 0.0636

         h = 13,205.4 m

b) For this part we are asked to use the law of universal gravitation, write the energy

starting point. Satellite surface

           Em₀ = K + U = ½ m v² - GmM / r_o

final point. Where the ball stops

            Em_{f}= U = - G mM / r_f

          Em₀ = Em_{f}

          ½ m v² - G m M / r_o = - G mM / r_f

In this case all distances are measured from the center of the satellite

         1 / rf = 1 / GM (-½ v² + G M / r_o)

     

let's calculate

         1 / rf = 1 / (6.67 10⁻¹¹ 3.75 10¹⁹) (- ½ 41 2 + 6.67 10⁻¹¹ 3.75 10¹⁹ / 1.98 105)

         1 / r_f = 3,998 10⁻¹¹(-840.5 + 12.63 10³)

          1 / r_f = 4,714 10⁻⁷

          r_f = 1 / 4,715 10⁻⁷

          r_f = 2.12 106 m

to measure this distance from the satellite surface

          r_f ’= r_f - r_o

          r_f ’= 2.12 106 - 1.98 105

         r_f ’= 1,922 106 m

c) the percentage difference is

          e% = 13 205.4 / 1,922 106 100

          e% = 0.68%

The estimate of part a is a little low

6 0
3 years ago
Ah electron is a negatively charged particle that has a charge of magnitude, e - 1.60 x 10-19 C. Which one of the following stat
Advocard [28]

Answer:

The correct statement is "The electric field is directed toward the electron and has a magnitude of \rm \dfrac{ke}{r^2} ".

Explanation:

According to Coulomb's law, the magnitude of the electric field due to a static point charge q at a point r distance away from it is given by

\rm E = \dfrac{k|q|}{r^2}.

  • k is the Coulmob's constant.

The direction of the electric field along the line joining the charge and the point where electric field is to be found and it is directed from positive charge to negative charge.

Conventionally, we assume a positive test charge placed at the point where electric field is to be found, the test charge has very small charge such that its charge does not affect the electric field due to the given charge.

The charge on the electron = -e.

The electric field due to an electron is given by

\rm E = \dfrac{k|-e|}{r^2}=\dfrac{ke}{r^2}.

The direction of this electric field is from positive test charge, placed at the point where electric field is to be found, towards the electron along the line joining the two.

Thus, the correct statement is "The electric field is directed toward the electron and has a magnitude of \rm \dfrac{ke}{r^2} ".

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3 years ago
Researchers at the University of Georgia have evaluated trends in streamside forests in areas within roughly 400 feet of the sta
Colt1911 [192]
<span>B: adds aesthetic value to the landscape. Think about it, out of all your options, that's the one that doesn't really help anything.

And I took the test, so take my word for it.</span>
6 0
3 years ago
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