All categories

4 years ago

The potential energy possessed by a molecule is dependent upon

Physics

1 answer:

lisabon 2012 [21]4 years ago

3 0

Answer:

Its composition and structure

Explanation:

The potential energy possessed by a molecule depends on its composition and structure. Its composition determines the type of intramolecular bonds present in the molecule and its structure determines the strength of the intramolecular bonds. Let's look at the example of the water molecule. It consists of two hydrogen atoms and one oxygen atom. The intramolecular bonds present here is the covalent O-H bond and since it has two O-H bonds in a molecule, and is V-shaped. These two properties determine the magnitude of the potential energy of the molecule.

You might be interested in

4. There are two categories of ultraviolet light. Ultraviolet A (UVA) has a wavelength ranging from 320 nm to 400 nm. It is not

vampirchik [111]

The ranges of frequency are:

UVA: $[7.50-9.38]\cdot 10^{14} Hz$

UVB: $[9.38-10.71]\cdot 10^{14} Hz$

Explanation:

The relationship between frequency and wavelength for an electromagnetic wave is the following:

$f = \frac{c}{\lambda}$

where

f is the frequency

$c=3.0\cdot 10^8 m/s$ is the speed of light

$\lambda$ is the wavelength

For the UVA, the range of wavelength is 320 nm - 400 nm, so

$\lambda_1 = 320 \cdot 10^{-9} m\\\lambda_2 = 400 \cdot 10^{-9} m$

So the corresponding frequencies are

$f_1 = \frac{3\cdot 10^8}{320\cdot 10^{-9}}=9.38\cdot 10^{14} Hz\\f_2= \frac{3\cdot 10^8}{400\cdot 10^{-9}}=7.50\cdot 10^{14} Hz$

For the UVB, the range of wavelength is 280 nm - 320 nm, so

$\lambda_1 = 280 \cdot 10^{-9} m\\\lambda_2 = 320 \cdot 10^{-9} m$

So the corresponding frequencies are

$f_1 = \frac{3\cdot 10^8}{280\cdot 10^{-9}}=1.07\cdot 10^{15} Hz\\f_2= \frac{3\cdot 10^8}{320\cdot 10^{-9}}=9.38\cdot 10^{14} Hz$

So the ranges of frequency are:

UVA: $[7.50-9.38]\cdot 10^{14} Hz$

UVB: $[9.38-10.71]\cdot 10^{14} Hz$

Learn more about waves, frequency and wavelength:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

3 0

3 years ago

Unpolarized light with intensity I0I0I_0 is incident on an ideal polarizing filter. The emerging light strikes a second ideal po

Montano1993 [528]

Answer:

A) I = Io 0.578, B) he light that leaves the polarized is completely polarized, being perpendicular to the axis of the second filter

Explanation:

A) Light passing through a polarizer must comply with the / bad law

I = Io cos2 tea

Where is at the angle of the polarizer and incident light

I = Io cos2 45

I = Io 0.578

Therefore the beam intensity is 0.578 of the incident intensity

.B) the light that leaves the polarized is completely polarized, being perpendicular to the axis of the second filter

3 0

4 years ago

Describe an object that floats in water and an object that sinks in water in

Leona [35]

Answer:

Buoyant Force: Cause and Calculation

The result is a net upward force (a buoyant force) on any object in any fluid. If the buoyant force is greater than the object's weight, the object will rise to the surface and float. If the buoyant force is less than the object's weight, the object will sink.

5 0

3 years ago

According to Newton’s Third Law, action and reaction are

Komok [63]

<span>B. equal and in opposite directions</span>

5 0

3 years ago

Read 2 more answers

- 3000 J of work is done on a 2kg object over a distance of 10m. What is the force acting on the object?

SpyIntel [72]

The answer is B. 300N

7 0

3 years ago