Answer:
A) high spin complex
B) low spin complex
Explanation:
A) VCI3(H20)3 is a high spin complex and this is because the complex has a weak field ligands all . this weak field ligands makes it impossible for pairing to take place
B) Fe(NH3)23 is a low spin complex and this is because the complex is made up of strong field ligands, this strong field ligands makes it possible for paring to take place
note : Ligands in which its donor atoms are ; Nitrogen,phosphorous or carbon are considered strong ligands
Answer: The sample of ammonium carbonate contains
0.560 mol NH
4
Explanation:The chemical formula for ammonium carbonate is
(
NH
4
)
2
CO
3
. The formula indicates that in one mole of ammonium carbonate, there are two moles of ammonium ions,
NH
4
Answer:
H-O-H polar
O-C-O nonpolar
H-C-N polar
Explanation:
Looking up the electronegativities of the atoms involved in this question, we have:
Atom Electronegativity
H 2.2
C 2.55
N 3.04
O 3.44
All of the atoms differ in electronegativity resulting in individual dipole moments in H-O, O-C, H-C and C-N bonds. To find if the molecules will be polar we need to consider the structure of the compound to see if there is a resultant dipole moment.
In H-O-H, we have 2 lone pairs of electrons around the central oxygen atom which push the angle H-O-H of the ideal tetrahedral structure to be smaller than 109.5 º resulting in an overall dipole moment making it polar.
In O-C-O, we have two dipole moments that exactly cancel each other in the linear molecule since the central carbon atom does not have lone pairs of electrons since it has 2 double bonds. Therefore the molecule is nonpolar.
In H-C-N, again we have have a central carbon atom without lone pairs of electrons and the shape of the molecule is linear. But, now we have that the dipole moment in C-N is stronger than the H-C dipole because of the difference in electronegativity of nitrogen compared to hydrogen. The molecule has an overall dipole moment and it is polar.
