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alexgriva [62]
3 years ago
14

What are the dangers while scuba diving?

Chemistry
1 answer:
antoniya [11.8K]3 years ago
3 0

Answer: The dangers are decompression sickness arterial air embolism, and of course drowning. There are also effects of diving, such as nitrogen narcosis, that can contribute to the cause of these problems.  And sea creatures like Great White Sharks, Lionfish, Sea snakes, Cone Snail, rays, The great barracuda, Flower Urchin, Stonefish, Blue Ringed Octopus. And more

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What should a simplified model of a large molecule like glucose show?
maxonik [38]

Glucose is the simplest sugar and carbohydrate that provides energy. The simplified model of glucose (C₆H₁₂O₆) shows carbon, hydrogen, and oxygen atoms linked together.

<h3>What is glucose?</h3>

Glucose is an example of a carbohydrate macromolecule that is further classified as a monosaccharide. They are crystalline and fundamental units of carbohydrates.

The molecular formula of glucose is C₆H₁₂O₆ and the mass is 180.156 g/mol. It is an aldohexose that contains an aldehydic functional group. In its structure, there are six oxygen atoms, six carbon atoms, and twelve hydrogen atoms.

Therefore, the glucose molecule is composed of C, H, and O.

Learn more about glucose here:

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1 year ago
Why would the electrolysis reaction stop if the battery was removed
s344n2d4d5 [400]

If the battery was removed, the energy produced by the battery would not be able to continue its path along the circuit.

8 0
2 years ago
PLEASE HELP WITH ENVI SCI QUESTION
Vladimir79 [104]
Different types of acid deposition are

sulphur dioxide
nitroges oxides
3 0
3 years ago
Which of the following processes are physical changes?
Stolb23 [73]
C) and d) are physical changes while b) is chemical
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3 years ago
Read 2 more answers
How many milliliters of 0.0896M LiOH are required to titrate 25.0 mL of 0.0759M HBr to the equivalence point?
slavikrds [6]

Answer:

V_{LiOH}=21.8mL

Explanation:

Hello,

In this case, during titration at the equivalence point, we find that the moles of the base equals the moles of the acid:

n_{LiOH}=n_{HBr}

That it terms of molarities and volumes we have:

M_{LiOH}V_{LiOH}=M_{HBr}V_{HBr}

Next, solving for the volume of lithium hydroxide we obtain:

V_{LiOH}=\frac{M_{HBr}V_{HBr}}{M_{LiOH}} =\frac{0.0759M*25.0mL}{0.0896M} \\\\V_{LiOH}=21.8mL

Best regards.

8 0
2 years ago
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