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alexgriva [62]
2 years ago
14

What are the dangers while scuba diving?

Chemistry
1 answer:
antoniya [11.8K]2 years ago
3 0

Answer: The dangers are decompression sickness arterial air embolism, and of course drowning. There are also effects of diving, such as nitrogen narcosis, that can contribute to the cause of these problems.  And sea creatures like Great White Sharks, Lionfish, Sea snakes, Cone Snail, rays, The great barracuda, Flower Urchin, Stonefish, Blue Ringed Octopus. And more

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Which of the following is a chemical property of a base?
juin [17]

Answer:

D) forms hydronium ions in water

Explanation:

Texture and conductivity are physical properties which makes answer A and B wrong. Answer C does not refer to a chemical reaction.

4 0
3 years ago
Read 2 more answers
A 2. 75-l container filled with co2 gas at 25°c and 225 kpa pressure springs a leak. When the container is re-sealed, the pressu
Serjik [45]

The number of moles of gas lost is  0.0213 mol. It can be solved with the help of Ideal gas law.

<h3>What is Ideal law ?</h3>

According to this law, "the volume of a given amount of gas is directly proportional to the number on moles of gas, directly proportional to the temperature and inversely proportional to the pressure. i.e.

PV = nRT.

Where,

  • p = pressure
  • V = volume (1.75 L = 1.75 x 10⁻³ m³)
  • T =  absolute temperature
  • n = number of moles
  • R =  gas constant, 8.314 J*(mol-K)

Therefore, the number of moles is

n = PV / RT

State 1 :

  • T₁ = (25⁰ C = 25+273 = 298 K)
  • p₁ = 225 kPa = 225 x 10³ N/m²

State 2 :

  • T₂ = 10 C = 283 K
  • p₂ = 185 kPa = 185 x 10³ N/m²

The loss in moles of gas from state 1 to state 2 is

Δn = V/R (P₁/T₁ - P₂/T₂ )

V/R = (1.75 x 10⁻³ m³)/(8.314 (N-m)/(mol-K) = 2.1049 x 10⁻⁴ (mol-m²-K)/N

p₁/T₁ = (225 x 10³)/298 = 755.0336 N/(m²-K)

p₂/T₂ = (185 x 10³)/283 = 653.7102 N/(m²-K)

Therefore,

Δn = (2.1049 x 10⁻⁴ (mol-m²-K)/N)*(755.0336 - 653.7102 N/(m²-K))

    = 0.0213 mol

Hence, The number of moles of gas lost is 0.0213 mol.

Learn more about ideal gas here ;

https://brainly.in/question/641453

#SPJ1

3 0
2 years ago
Calculate the missing variables in each experiment below using Avogadro’s law.
blagie [28]

Answer:

The answer to your question is: letter c

Explanation:

Data

V1 = 612 ml    n1 = 9.11 mol

V2 = 123 ml    n2 = ?

Formula

                               \frac{V1}{n1}  =  \frac{V2}{n2}

                                         n2 = \frac{n1V2}{V1}

                                         n2 = \frac{(9.11)((123)}{(612)}

                                                n2 = 1.83 mol                                                

5 0
2 years ago
What is a variable and what do it do
frosja888 [35]
Varuable, In algebra, a symbol (usually a letter) standing in for an unknown numerical value in an equation :)
3 0
3 years ago
Read 2 more answers
Determine the molecular weight of H20.<br> o 18 g<br> O 18.0 g<br> O 18.01 g<br> O 18.016 g
Sonbull [250]

Answer:

The correct answer is D

<u>18.016 g</u>

<u></u>

Explanation:

Molecular Weight : It is the sum of atomic weights of each atoms present in the compound.

The molecular weught is measured in atomic mass.unit( amu) or simply"u"

This is calculated by using :

Molecular weight = number of atom x atomic mass of the atom

For H2O

Number of H atoms = 2

Number of O atom = 1

Molecular weight of H2O = 2(mass of H atom) + 1(mass of O atom)

Molecular weight = 2(1.00784) + 15.999

= 18.01558 u

= 18.016 u

8 0
2 years ago
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