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2 years ago

11

14. A 2.5 kg object is experiencing a net force of 50 N while traveling in a circle at a velocity of 5.0 m/s. What is the radius

of its motion?

1 answer:

lara31 [8.8K]2 years ago

6 0

Answer:

1.25 meters

Explanation:

Given data

Mass= 2.5kg

Force= 50N

velocity= 5m/s

r=????

Applying the formula

F= mv^2/r

Make r subject of formula

r= mv^2/F

r= 2.5*5^2/50

r= 2.5*25/50

r=62.5/50

r=1.25 meters

Hence the radius is 1.25 meters

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<u>Answer:</u> The final temperature of the solution is $80.14^oC$

<u>Explanation:</u>

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$T_{final}$ = final temperature = ?

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