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Lorico [155]
3 years ago
8

A subatomic particle that has no charge and very mass is called

Physics
2 answers:
V125BC [204]3 years ago
6 0

    the answer would be Neutrino because Neutrino, elementary subatomic particle with no electric charge, very little mass, and 12 unit of spin. Neutrinos belong to the family of particles called leptons, which are not subject to the strong force.

emmasim [6.3K]3 years ago
5 0

Answer:

A. neutrino

Explanation:

Neutrino, elementary subatomic particle with no electric charge, very little mass, and 12 unit of spin. Neutrinos belong to the family of particles called leptons, which are not subject to the strong force.

Glad I could help!!

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A car accelerates from rest at a constant rate of 3.5m/s^2. What is the velocity of the car 12s later?
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I think 42… sorry if its wrong :( hope it helps..
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study a 75kg person stands on a scale in an elevator what does read in n and in kg when the elevator is at rest?
Verdich [7]

To solve this problem we will use Newton's second law in order to obtain the weight of a person. The second law tells us that

F = ma

Where,

m = mass

a = Acceleration

In this particular case, the acceleration is equal to that exerted by the earth through gravitational acceleration, so if the person's weight is 75Kg and the gravity is 9.8m / s^2 , the weight of the body will be,

F_W =mg

F_W = (75kg)(9.8m/s^2 )

F_W = 735.75N

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3 years ago
(Hypothetical question)<br> If the earth was square and not round what would it be like
Nuetrik [128]

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8 0
2 years ago
Read 2 more answers
A river flows due south with a speed of 2.0 m/s .You steer a motorboat across the river; your velocity relative to the water is
mihalych1998 [28]

Answer:

a) v_m =\sqrt{v^2_x + v^2_y} = \sqrt{(2m/s)^2 +(4.8 m/s)^2}= 5.2 m/s

b) \theta= tan^{-1} \frac{v_y}{v_x} = tan^{-1} (\frac{2}{4.8})= 22.62 degrees and on this case to the South of the East.

c)t= \frac{w}{v_m}= \frac{600m}{4.8 m/s}= 125 s

d) Y = 2 m/s * 125 s = 250m

So it would be 250 to the South

Explanation:

Part a

For this case the figure attached shows the illustration for the problem.

We know that v_y = 2 m/s represent the velocity of the river to the south.

We have the velocity of the motorboard relative to the water and on this case is V_x= 4.8 m/s

And we want to find the velocity of the motord board relative to the Earth v_m

And we can find this velocity from the Pythagorean Theorem.

v_m =\sqrt{v^2_x + v^2_y} = \sqrt{(2m/s)^2 +(4.8 m/s)^2}= 5.2 m/s

Part b

We can find the direction with the following formula:

\theta= tan^{-1} \frac{v_y}{v_x} = tan^{-1} (\frac{2}{4.8})= 22.62 degrees and on this case to the South of the East.

Part c

For this case we can use the following definition

D = Vt

The distance would be D = w = 600 m and the velocity V = 4.8m/s and if we solve for t we got:

t= \frac{w}{v_m}= \frac{600m}{4.8 m/s}= 125 s

Part d

For this case we can use the same definition but now using the y compnent we have:

Y = v_y t

And replacing we got:

Y = 2 m/s * 125 s = 250m

So it would be 250 to the South

7 0
3 years ago
Suppose 500 joules of work is done to push an object in 15 seconds. Find the power for this situation
ohaa [14]

Answer:

You have to calculate

Explanation:

Work is done when a force that is applied to an object moves that object. The work is calculated by multiplying the force by the amount of movement of an object (W = F * d). A force of 10 newtons, that moves an object 3 meters, does 30 n-m of work.

5 0
4 years ago
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