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2. It is now 10:29 a.m., but when the bell rings at 10:30 a.m. Suzette will be late for French class for the third time this wee

Alex17521 [72]

Answer:

62 seconds
no

Explanation:

The total travel time Suzette experiences is the sum of the times in each hallway. Using

time = distance/speed

we can add the times.

(35.0 m)/(3.50 m/s) +(48.0 m)/(1.20 m/s) +(60 m)/(5.0 m/s)

= 10 s + 40 s + 12 s

= 62 s

It takes Suzette 62 seconds to get to class. She does not beat the bell.

3 0

3 years ago

A crate slides down a ramp that makes a 20o angle with the ground. To keep the crate moving at a steady speed, Paige pushes back

cupoosta [38]

Answer:

-223.64684 J

Explanation:

F = Force that is applied to the crate = 68 N

s = Displacement of the crate = 3.5 m

$\theta$ = Angle between the force and displacement vector = (180-20)

Work done is given by

$W=Fscos\theta\\\Rightarrow W=68\times 3.5\times cos(180-20)\\\Rightarrow W=-223.64684\ J$

The work that Paige does on the crate is -223.64684 J

6 0

3 years ago

A 9.0-V battery (with nonzero resistance) and switch are connected in series across the primary coil of a transformer. The secon

qwelly [4]

Answer:

N₂ / N₁ = 13.3

Explanation:

A transformer is a system that induces a voltage in the secondary due to the variation of voltage in the primary, the ratio of voltages is determined by the expression

ΔV₂ = N₂ /N₁ ΔV₁

where ΔV₂ and ΔV₁ are the voltage in the secondary and primary respectively and N is the number of windings on each side.

In this case, they indicate that the primary voltage is 9.0 V and the secondary voltage is 120 V

therefore we calculate the winding ratio

ΔV₂ /ΔV₁ = N₂ / N₁

N₂ / N₁ = 120/9

N₂ / N₁ = 13.3

s good clarify that in transformers the voltage must be alternating (AC)

3 0

3 years ago

Red light of wavelength 633 nm from a helium-neon laser passes through a slit 0.320 mm wide. The diffraction pattern is observed

DanielleElmas [232]

Answer:

$W = 10.28\ mm$

Explanation:

Given,

Red light wavelength = 633 nm

width of slit = 0.320 mm

distance,d = 2.60 m

Condition of first maximum

$a sin \theta_1 = m\lambda$

$\theta_1 =sin^{-1}(\dfrac{m\lambda}{a})$

m = 1

$\theta_1 =sin^{-1}(\dfrac{633\times 10^{-9}}{0.32\times 10^{-3}})$

$\theta_1 = 0.1133^\circ$

Width of the first minima

$y_1 = L tan \theta_1$

$y_1 = 2.60\times tan( 0.11331)$

$y_1 = 5.14 \ mm$

Now, width of the central region

$W = 2 y_1$

$W = 2\times 5.14$

$W = 10.28\ mm$

8 0

3 years ago

What is the answer to the question?

Masja [62]

Answer:

Explanation:

The y component is measured by the horizontal component and the vertical component. Together they determine the magnitude of the vector. In this case, the y or vertical component is found by using the sine function.

Formula

Sin(angle) = vector resultant / y component component.

Givens

angle = 42 degrees.

vector = 419 degrees

Solution

sin(42) = y / 419 Multiply both sides by 419

419 * sin(42) = 419 * y / 419

y = 419 * 0.6691

y = 280.37

Note

The vector is pointing downward so technically the vertical component should be negative. I'm not sure what to tell you to answer. I would try - 280.37, but if the computer marks you wrong, try 280.37 (no minus sign).

7 0

3 years ago