Among these two compounds
Lactic Acid is completely soluble in water (1000 g/L) while,
Myristic Acid is insoluble in water [<span>20 mg/L (20 °C)].
Explanation:
Among other factors solubility greatly depends upon the inter-molecular interactions between solute and solvent (
<em><u>LIKE DISSOLVES LIKE</u></em><u>)</u>. Greater the interactions greater is the solubility.
As shown below, Lactic Acid contains two hydroxyl groups and one carbonyl group. These three groups are involved in forming Hydrogen Bond Interactions with the molecules of Water.
Whereas, Myristic Acid contains a long chain of carbon which is non polar in nature. So, due to this non polar carbon chain no such interactions are formed as formed in case of Lactic Acid. Still the less solubility found is due to the interaction of Carboxylic group of Myristic Acid with water molecules, which is comparatively very less.</span>
Answer:
120g
Explanation:
Step 1:
We'll begin by writing the balanced equation for the reaction.
Sn + 2HF —> SnF2 + H2
Step 2:
Determination of the number of mole HF needed to react with 3 moles of Sn.
From the balanced equation above,
1 mole of Sn and reacted with 2 moles of HF.
Therefore, 3 moles Sn will react with = 3 x 2 = 6 moles of HF.
Step 3:
Conversion of 6 moles of HF to grams.
Number of mole HF = 6 moles
Molar Mass of HF = 1 + 19 = 20g/mol
Mass of HF =..?
Mass = number of mole x molar Mass
Mass of HF = 6 x 20
Mass of HF = 120g
Therefore, 120g of HF is needed to react with 3 moles of Sn.
Answer:
8.75 mL
Explanation:
First, we calculate the molar mass of NaCl = molar mass of Na + molar mass of Cl. Molar mass of Na = 23 g/mol, molar mass of Cl = 35.5 g/mol.
So molar mass NaCl = (23 + 35.5) g/mol = 58.5 g/mol. The number of moles ,n of NaCl in 12.5g is n = mass of NaCl/ molar mass NaCl = 12.5 g / 58.5 g/mol = 0.214 mol.
The molarity, M of 150 mL M = number of moles/ volume = 0.214 mol / 150 mL = 1.427 M.
We now calculate the number of moles of NaCl in 250 mL of 0.500 M.
Number of moles, n = molarity × volume. molarity = 0.500 M, volume = 250 mL. So n = 0.500 × 250 = 0.125 moles. Since we have 0.125 moles in the dilute 250 mL solution, the volume of the 150 mL 1.43 M solution required is number of moles in 250 mL solution/molarity of 150 mL solution = 0.125 mol / 1.427 M = 0.0875 L = 8.75 mL
The color change would only effect the appearance of the substance, so it would be a physical change.
Answer: physical change