As we know,
1 D = 3.34 × 10⁻³⁰ C.m
So,
1.44 D = ?
Solving for 1.44 D,
= (3.34 × 10⁻³⁰ C.m × 1.44 D) ÷ 1 D
1.44 D = 4.80 × 10⁻³⁰ C.m
Dipole Moment is given as,
Dipole Moment = q × r
Solving for q,
q = Dipole Moment / r ------ (1)
Where,
Dipole Moment = 4.80 × 10⁻³⁰ C.m
r = 163 pm = 1.63 × 10⁻¹⁰ m
Putting values in eq. 1,
q = 4.80 × 10⁻³⁰ C.m / 1.63 × 10⁻¹⁰ m
q = 2.94 × 10⁻²⁰ C
As,
1.602 × 10⁻¹⁹ C = 1 e⁻
So,
2.94 × 10⁻²⁰ C = X e⁻
Solving for X,
X = (2.94 × 10⁻²⁰ C × 1 e⁻) ÷ 1.602 × 10⁻¹⁹ C
= 0.183 e⁻
Result:
So one element is containing + 0.183 e⁻ while the other element is containing - 0.183 e⁻.
Answer:
2.25×10¯³ mm.
Explanation:
From the question given above, we obtained the following information:
Diameter in micrometer = 2.25 μm
Diameter in millimetre (mm) =?
Next we shall convert 2.25 μm to metre (m). This can be obtained as follow:
1 μm = 1×10¯⁶ m
Therefore,
2.25 μm = 2.25 μm / 1 μm × 1×10¯⁶ m
2.25 μm = 2.25×10¯⁶ m
Finally, we shall convert 2.25×10¯⁶ m to millimetre (mm) as follow:
1 m = 1000 mm
Therefore,
2.25×10¯⁶ m = 2.25×10¯⁶ m /1 m × 1000 mm
2.25×10¯⁶ m = 2.25×10¯³ mm
Therefore, 2.25 μm is equivalent to 2.25×10¯³ mm.
I think the answer would be dependent variable. An unknown or changeable quantity is called a dependent variable. It <span>is what you measure in the experiment and what is affected during the experiment. Hope this answers the question. Have a nice day.</span>
Answer:
the answer is v and z. you can see the pic
