Answer:

Explanation:
<u>Given Data:</u>
Acceleration due to gravity = g = -9.8 m/s²
Maximum Height = h = 0.490 m
At h,
= 0
<u>Required:</u>

<u>Formula:</u>

<u>Solution:</u>
Put the givens
![2 (-9.8) (0.490) = (0)\² - v_o^2\\\\-9.604=-v_o^2\\\\9.604=v_o^2\\\\Take \ sqrt\ on \ both \ sides\\\\\sqrt{9.604}=v_o^2\\\\3.1 \ m/s=v_o\\\\v_o=3.1\ m/s\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=2%20%28-9.8%29%20%280.490%29%20%3D%20%280%29%5C%C2%B2%20-%20v_o%5E2%5C%5C%5C%5C-9.604%3D-v_o%5E2%5C%5C%5C%5C9.604%3Dv_o%5E2%5C%5C%5C%5CTake%20%5C%20sqrt%5C%20on%20%5C%20both%20%5C%20sides%5C%5C%5C%5C%5Csqrt%7B9.604%7D%3Dv_o%5E2%5C%5C%5C%5C3.1%20%5C%20m%2Fs%3Dv_o%5C%5C%5C%5Cv_o%3D3.1%5C%20m%2Fs%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Answer:
<h2>1320 J</h2>
Explanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 600 × 2.2
We have the final answer as
<h3>1320 J</h3>
Hope this helps you
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