<span>The solution for this
problem is:</span>
density = mass / volume <span>
7860 = 1 / ((4/3) pi r^3)
r^3 = 1 / (7860 * 4/3*pi)
r = (1 / (7860 * 4/3*pi))^(1/3)</span>
= 0.067 m <span>
Inertia = (2/5)mr^2</span>
= (2/5) x 1 x 0.067^2
= 0.0017956 kg-m^2 <span>
1/2.3 = 0.4348 rev/s
0.4348 x 2pi = 2.732 rad/s
Angular momentum = Inertia x rad/s
0.0017956 x 2.732 = 0.00490557 kg m^2/s</span>
Answer:
(v-u) = 1.27 m/s
Explanation:
Given that,
Mass of a car, m = 1100 kg
Force with which the wall strikes, F = 4000 N
Time, t = 0.35 s
We need to find the change in velocity of the car.
The net force acting on the car is given by :
F = ma
a is acceleration

(v-u) is the change in velocity. Hence, the change in the velocity of the car is 1.27 /s.
391.12 *
mass is required for activity of 315 ci
The activity of the radioactive substance is the number of disintegrations taking place in a radioactive sample.
Isotopes are the members of an element having the same number of protons but the different number of neutrons.
the activity of the radioactive sample is given as:
A = λ * N
where λ is the decay constant and N is the number of disintegrations.
activity is given as 315 ci
A = 315 * 3.7 * 
= 1165.5 *
Bq
λ = 0.693 / 
= 0.693 / 2.69 * 24 * 3600
= 2.98 *
t^-1
Therefore, N = A / λ
= 1165.5 *
/ 2.98 * 
N = 391.12 * 
391.12 *
mass is required for activity of 315 ci
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Answer:
1800 m/s
Explanation:
The equation is v = fλ
λ= 0.75
f = 2400 Hz
V = 2400 × 0.75
V = 1800 m/s
[ you did not give units for wavelength, I assumed it would be m/s]