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Rasek [7]
3 years ago
5

8. Which gas contributes the largest part of air? *

Chemistry
1 answer:
timurjin [86]3 years ago
5 0

Answer:

Nitrogen

Explanation:

Nitrogen present 78% in the earth's atmosphere

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Explain, in terms of electron configuration why atoms of the radioisotope produced by the sixth decay in the U-238 disintegratio
Troyanec [42]

Answer:

The reason they don't react is because Elements with full octets are stable, the Elements with no unpaired electrons do not react at all in the decay.

4 0
3 years ago
If 65.5 moles of an ideal gas is at 9.15 atm at 50.30 °C, what is the volume of the gas?
qwelly [4]
To calculate for the volume, we need a relation to relate the number of moles (n), pressure (P), and temperature (T) with volume (V). For simplification, we assume the gas is an ideal gas. So, we use PV=nRT.

PV = nRT  where R is the universal gas constant
V = nRT / P
V = 65.5 ( 0.08205 ) (273.15 + 50.30) / 9.15 
V = 189.98 L
7 0
3 years ago
Why was it important to establish the Clean Air Act?
deff fn [24]

Answer:

C.

Explanation:

The Clean Air Act was enacted in 1973 and brought to action in 1990. The act was passed to supervise air emissions to ensure clean air and atmosphere for people. The act was passed in the wake of premature deaths of hundred of thousands people. The act works with NAAQS to ensure safe and clean air for the safety of public health.

<u>From the given options the correct one is C. The Clean Air Act supervises the activities which emits air and any activities that is found to pollute the air will be labelled as illegal</u>.

Therefore, option C is correct.

5 0
3 years ago
How many atoms are there in each of the following ?a.)1.50 mol Na c.) 0.250 mol. Sib.)6.755 mol Pb
tamaranim1 [39]
a) \: n = \frac{N}{NA} \\ 1.5 = \frac{x}{6.02 \times \: {10}^{23} } \\ x = 1.5 \times 6.02 \times {10}^{23} \\ x = 9.03 \times {10}^{23} \: atoms \: of \: Na

b) \: n = \frac{N}{NA} \\ 0.25 = \frac{x}{6.02 \times \: {10}^{23} } \\ x = 0.25 \times 6.02 \times {10}^{23} \\ x = 1.505 \times {10}^{23} \: atoms \: of \: Si \:
c) \: n = \frac{N}{NA} \\ 6.755 = \frac{x}{6.02 \times \: {10}^{23} } \\ x = 6.755 \times 6.02 \times {10}^{23} \\ x = 40,6651 \times {10}^{23} \\ x = 4.07 \times {10}^{24} \: atoms \: of \: Pb \:
5 0
3 years ago
Temperature and Thermal Er
gtnhenbr [62]

Explanation:

50 degrees fahrenheit =

10 degrees celsius

7 0
3 years ago
Read 2 more answers
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