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Svet_ta [14]
3 years ago
5

En la sopa de letras se encuentran 14 conceptos y nombres

Chemistry
1 answer:
Vinil7 [7]3 years ago
3 0
PeLdon xd , no c que es “ vectora “ JSJS
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Molar mass (easy but I’m lazy)
grin007 [14]

Answer:

dont be lazy

Explanation:

I didnt do cuz im lazy

:p

4 0
2 years ago
Which of the following statements is correct about the gases which participate in photosynthesis? (5 points)
aleksklad [387]

Answer:

Carbon dioxide is used up, and oxygen is produced.

Explanation:

For photosynthesis to occur the plant need carbon dioxide water and sunlight to convert it into glucose for it to eat and oxygen is a byproduct of the chemical reaction.

4 0
3 years ago
Predict whether a precipitation reaction will occur when aqueous solutions of pbcl2 and (nh4)2s
Nutka1998 [239]
Answer : YES, The precipitation reaction will occur.

Explanation : When we mix the aqueous solutions of Lead chloride and Ammonium sulfide a reaction will occur which is stated below :

PbCl_{2} +(NH_{4}) _{2} S ----\ \textgreater \  PbS + 2[ (NH_{4})Cl]

The major product that is formed is Lead sulfate which is black in colour.

Once the reaction is complete one can observe a black precipitate getting obtained. 
5 0
3 years ago
A bicycle tire is filled with air to a pressure of 100. psi at a temperature of 19C. Riding the bike on asphalt on a hot day inc
Zigmanuir [339]

Considering the direct relationship between pressure and temperature, the new pressure in the bicycle tire would be 63.01 psi

<h3>Gas law</h3>

The general gas laws is given by:

  P1V1/T1 = P2V2/T2

Where P1 = initial pressure V1 = initial volume T1 = initial temperature, P2 = final pressure, V2 = final volume, and T2 = final temperature.

In this case, P1 = 100 psi, V1 = 1, T1 = 19+273 = 292, P2 = ?, V2 = 1.4, T2 = 58+273 = 331

P2 = P1V1T2/T1V2

        = 100x1x292/331x1.4

                   = 63.01 psi

More on gas laws can be found here: brainly.com/question/1190311

5 0
2 years ago
Find the mass in kilograms of the liquid air that is required to produce 600L of oxygen. In normal condition, 1L of liquid air h
IgorC [24]

Mass in kilograms of liquid air required = 0.78 kg

<u>Given that </u>

1 Litre of liquid air contains 1.3 grams of oxygen ( air )

<u />

<u> Determine the a</u><u>mount of liquid air</u><u> in Kg</u>

volume of air given = 600 L

mass of liquid air required = x

1 litre = 1.3 grams

600 L =  x

∴ x ( mass of liquid air ) = 1.3 * 600

                                       = 780 g  = 0.78 kg

Hence we can conclude that Mass in kilograms of liquid air required = 0.78 kg

Learn more about liquid air : brainly.com/question/636295

3 0
2 years ago
Read 2 more answers
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