Answer:
Explanation:
Hello!
In this case, since the net ionic equations are ionic representations of the molecular equation in which the spectator ions (those at both reactants and products sides) are cancelled out, we first write the complete ionic equation for this reaction, considering that the solid silver chloride is not ionized due to its precipitation:
Whereas the nitrate and sodium ions are cancelled out for the aforementioned reason as they are the spectator ions, to obtain:
Which is the required net ionic equation.
Best regards!
A monomer is made up of a nitrogenous base, a five-carbon sugar, and a phosphate group bonded together. Hence, option A is correct.
<h3>What is a lipid?</h3>
A lipid is any of various organic compounds that are insoluble in water.
The smallest units of DNA are called nucleotides. These are organic molecules that serve as building blocks of DNA and RNA. They are monomers or subunits of nucleic acids like RNA and DNA. It is made up of a nitrogenous base, deoxyribose (five-carbon sugar), and at least one phosphate group.
They serve an important role in the metabolism of cells because they carry packets of energy in the form of nucleoside triphosphates (e.g. ATP, GTP, CTP, and UTP). They also play an important factor in cell signalling through enzymatic reactions and productions.
Hence, A monomer is made up of a nitrogenous base, a five-carbon sugar, and a phosphate group bonded together.
Learn more about lipids here:
brainly.com/question/1024207
#SPJ1
Answer:
That is NOT true!
Explanation:
No matter how little or big amount of waste you add, it is still pollution, and it adds to the big amount that is already there.
<h3>
Answer:</h3>
2.125 g
<h3>
Explanation:</h3>
We have;
- Mass of NaBr sample is 11.97 g
- % composition by mass of Na in the sample is 22.34%
We are required to determine the mass of 9.51 g of a NaBr sample.
- Based on the law of of constant composition, a given sample of a compound will always contain the sample percentage composition of a given element.
In this case,
- A sample of 11.97 g of NaBr contains 22.34% of Na by mass
A sample of 9.51 g of NaBr will also contain 22.345 of Na by mass
% composition of an element by mass = (Mass of element ÷ mass of the compound) × 100
Mass of the element = (% composition of an element × mass of the compound) ÷ 100
Therefore;
Mass of sodium = (22.34% × 9.51 g) ÷ 100
= 2.125 g
Thus, the mass of sodium in 9.51 g of NaBr is 2.125 g
For this problem, we are simply asked to convert from units of moles to units of mass. To do this, we need a factor to multiply to the original value. We will be using the molar mass of the compound. For CH4, the molar mass would be 16 g/mol. We do as follows:
mass = 0.35 mol CH4 ( 16 g / 1 mol) = 5.6 g CH4
Therefore, the correct answer is the second option.