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Svet_ta [14]
3 years ago
5

En la sopa de letras se encuentran 14 conceptos y nombres

Chemistry
1 answer:
Vinil7 [7]3 years ago
3 0
PeLdon xd , no c que es “ vectora “ JSJS
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What is the Electron Center Geometry of a CH3 carbon.
wel

Answer:

tetrahedral geometry

<h3>CHCH2O- CH2CH3</h3>

Explanation:

There are several centers of interest. Each carbon with all single bonds is the center of a tetrahedral geometry.

6 0
3 years ago
How many grams of calcium chloride were used if 2.485 grams of calcium oxalate monohydrate were produced, assuming a 100% yield.
DochEvi [55]

Answer:

54 G

Explanation:

5 0
3 years ago
If the length of a string increases 2 times but the mass of the string remains constant, the new density of the string will equa
Genrish500 [490]

If the length of a string increases 2 times but the mass of the string remains constant, the original density  will be multiplied by a factor  mathematically given as

v=1.414 times

<h3>Will the new density of the string equal the original density multiplied by what factor?</h3>

Generally, the equation for the  volume is mathematically given as

v = sqt(TL/m)

Where

density = mass/length

Therefore

v2/v1 = \sqrt{L2/L1}

v2/v1 = \sqrt{2}

In conclusion,v ratio will give us

v=1.414 times

Read more about volume

brainly.com/question/1578538

8 0
2 years ago
A 275 g sample of a metal requires 10.75 kJ to change its temperature from 21.2 oC to its melting temperature, 327.5 oC. What is
Vlada [557]

Answer:

c=0.127\ J/g^{\circ} C

Explanation:

Given that,

Mass of the sample, m = 275 g

It required 10.75 kJ of heat to change its temperature from 21.2 °C to its melting temperature, 327.5 °C.

We need to find the specific heat of the metal. The heat required by a metal sample is given by :

Q=mc\Delta T

c is specific heat of the metal

c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{10.75\times 10^3\ J}{275\times (327.5 -21.2)}\\\\=0.127\ J/g^{\circ} C

So, the specific heat of metal is 0.127\ J/g^{\circ} C.

4 0
3 years ago
Potassium chlorate decomposes into potassium chloride and oxygen gas. How many grams of oxygen are produced when 1.06 grams of p
kifflom [539]

The amount of oxygen that are produced when 1.06 grams of potassium chlorate decompose completely is 0.64 grams.

<h3>What is the relation between mass & moles?</h3>

Relation between the mass and moles of any substance will be represented as:

  • n = W/M, where
  • W = given mass
  • M = molar mass

Moles of potassium chlorate = 1.66g / 122.5g/mol = 0.0135mole

Given chemical reaction is:

2KClO₃ → 2KCl + 3O₂

From the stoichiometry of the reaction, it is clear that:

2 moles of KClO₃ = produces 3 moles of O₂

0.0135 moles of KClO₃ = produces (3/2)(0.0135)=0.02 moles of O₂

Mass of oxygen = (0.02mol)(32g/mol) = 0.64 g

Hence produced mass of oxygen is 0.64 grams.

To now more about mass & moles, visit the below link:
brainly.com/question/18983376

#SPJ1

5 0
2 years ago
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