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2 years ago

Identify the metal by comparison to table 2.4 in the textbook

1 answer:

4 0

Answer is: metal is lead with density of 11,4 g/cm³.
Text that missing: a sample of an unkwown metal has a mass of 35,4 g and a volume of 3,11 cm³.
m(metal) = 35,4 g.
V(metal) = 3,11 cm³.
d(metal) = m(metal) ÷ V(metal)
d(metal) = 35,4÷ g ÷ 3,11 cm³
d(metal) = 11,4 g/cm³.

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What is the relatioship between atomic numbers and ionic radii of the elements in Group 1? what is the relationship between atom

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As atomic number increases atomic radii also increase down group 1. ionisation energy down group 1 will also decrease because as atomic radii gets bigger there is less electrostatic force between nuclei and electrons so less energy needed to remove valence electron.

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2 years ago

Which of the following will dissociate into the largest number of ions in solution?

Svetlanka [38]

Answer:D

Explanation:

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3 years ago

Be sure to answer all parts. Consider the formation of ammonia in two experiments. (a) To a 1.00−L container at 727°C, 1.30 mol

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Answer: The value of $K_c$ for $2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)$ reaction is $5.13\times 10^2$

Explanation:

We are given:

Initial moles of nitrogen gas = 1.30 moles

Initial moles of hydrogen gas = 1.65 moles

Equilibrium moles of ammonia = 0.100 moles

Volume of the container = 1.00 L

For the given chemical equation:

$N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)$

Initial: 1.30 1.65

At eqllm: 1.30-x 1.65-3x 2x

Evaluating the value of 'x'

$\Rightarrow 2x=0.100\\\\\Rightarrow x=0.050mol$

The expression of $K_c$ for above equation follows:

$K_c=\frac{[NH_3]^2}{[N_2]\times [H_2]^3}$

Equilibrium moles of nitrogen gas = $(1.30-x)=(1.30-0.05)=1.25mol$

Equilibrium moles of hydrogen gas = $(1.65-x)=(1.65-0.05)=1.60mol$

Putting values in above expression, we get:

$K_c=\frac{(0.100)^2}{1.25\times (1.60)^3}\\\\K_c=1.95\times 10^{-3}$

Calculating the $K_c'$ for the given chemical equation:

$2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)$

$K_c'=\frac{1}{K_c}\\\\K_c'=\frac{1}{1.95\times 10^{-3}}=5.13\times 10^2$

Hence, the value of $K_c$ for $2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)$ reaction is $5.13\times 10^2$

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2 years ago

Read 2 more answers

At what height the acceleration due to gravity of the earth become half ?

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Answer:

Acceleration due to gravity is reduced to half its value on the earth's surface at an altitude of 2.65×106 m

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2 years ago

Compared to the normal freezing point and boiling point of water, a 1-molar solution of sugar in water will have a

marysya [2.9K]

Answer :

Boiling point of the sugar solution will be higher than that of water's boling point.
Freezing point of the sugar solution will be lower than that of water's freezing point.

Explanation:

Boiling point of a liquid is defined as temperature at which vapor pressure of liquid becomes equal to the atmospheric pressure.

Boiling point of solution is always higher than that of the pure solvent

Vapor pressure increases with increase in temperature which means sugar solution will be heated more to make vapor pressure equal to atmospheric pressure.

Freezing point is defined as temperature at which solid and liquid phase are at equilibrium or temperature at which vapor pressure of liquid becomes equal to the vapor pressure in its solid phase.

Freezing point of solution is always lower than that of the pure solvent.

Lower the temperature, lower will be the vapor pressure which sugar solution solution will get freeze at lower temperature than that of the water.

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2 years ago