You should have the velocity as a function of time either given explicitly or implicitly (a graph)
v = ds/dt (differentiating the position vector)
integrating the acceleration.
you can use impulse or work and energy principle and also newton law of motion to find acceleration then velocity
NOT SURE IF THAT WHAT YOU WANT.
Work<span> done is generally referred in </span>relation<span> to the force applied while energy is used in reference to other factors such as heat. </span>Power<span> is defined as </span>work<span> done per unit time. Or energy per unit time. Eg: if you supply 50 joules over a period of 5 seconds, you have supplied 50/5=10 Watts of </span>power<span>.</span>
Yes I'm pretty sure you can
Answer:
Angle θ ≅ 21.5°
Explanation:
Given:
speed Vi= 60 m/s, Range R= 250 m, g=9.81 m/s²
To find:
Angle θ = ?
Sol: we know that Rang R = Vi² sin 2θ / g
⇒ Sin 2θ = g×R / Vi²
Sin 2θ = (9.81 m/s² × 250 m) / ( 60 m/s)²
Sin 2θ = 0.68125
2θ = Sin ⁻¹ (0.68125)
2θ = 42.9413
θ = 42.9413 / 2
θ = 21.4706 ≅ 21.5°