Answer:
I don't know ☺️☺️☺️❌‼️
Explanation:
I don't understand this question
Answer:
there hope it can help.......
Answer:
ρ=962.16kg/m^3
Explanation:
The first thing we must do to solve is to find the mass of the specimen using the weight equation
w = mg
m=w/g
m=0.45/9.81=0.04587kg
To find the volume we must make a free-body diagram on the specimen, taking into account that the weight will go down and the buoyant force up, and the result of that subtraction will be the measured weight value (0.081N).
We must bear in mind that the principle of archimedes indicates that the buoyant force is given by
F = ρgV
where V is the specimen volume and ρ is the density of alcohol = 789kg / m ^ 3
considering the above we have the following equation
0.081=0.45-(789)(9.81m/s^2)V
solving for V
V=(0.081-0.45)/(-789x9.81)
V=4.7673x10^-5m^3
finally we found the density
ρ=m/v
ρ=0.04587kg/4.7673x10^-5m^3
ρ=962.16kg/m^3
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Based on the average velocity at section 2, and the absolute pressures at both sectors, the average speed at section 1 is 2.226 m/s.
<h3>What is the average speed at section 1?</h3>
Density at P₁:
= (40 + 100) / (0.287 x (40 + 273))
= 1.5585 kg/m³
Density at P₂:
= (10 + 100) / (0.287 x (40 + 273))
= 1.2245 kg/m³
The average speed at section 1 is:
= (Density at P₂ x d² x 25.5) / (Density at P₁ x 9d²)
= 2.226 m/s
Find out more on average velocity at brainly.com/question/17444459.
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