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svetoff [14.1K]
2 years ago
5

At what distance from the Earth’s surface is a 10,000 kg satellite if its potential energy is equal to –5.58 x 1011 J? (choose t

he closest answer)
A 958 km

B 858.km

C 758 km

D 658 km
Engineering
1 answer:
Maksim231197 [3]2 years ago
3 0

Answer:

Option D

Explanation:

As we know

Gravitational Constant (G) = 6.67*10^{11}

Mass of Earth (M) = 5.98*10^{24}

Weight of satellite (m) = 10,000 Kg

Radius of Earth (R) = 6.378*10^6

Distance of satellite from Earth = \frac{GMm}{R} - U

Substituting the given values, we get

D=\frac{(-((6.67*10^{11})(5.98*10^{24})(10000))}{(6.378*10^6)} - (-5.58*10^{11})\\\\0.625*10^{3}Km

or 635 m

The correct answer is option D

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Design a half-wave recti er which provides a peak voltage of 15 V, and anaverage voltage of 3.8 V when driven by a 120 V (rms) a
nirvana33 [79]

Answer:

You need a 120V to 24V commercial transformer  (transformer 1:5), a 100 ohms resistance, a 1.5 K ohms resistance and a diode with a minimum forward current of 20 mA (could be 1N4148)

Step by step design:

  1. Because you have a 120V AC voltage supply you need an efficient way to reduce that voltage as much as possible before passing to the rectifier, for that I recommend a standard 120V to 24V transformer.  120 Vrms = 85 V and 24 Vrms = 17V = Vin
  2. Because 17V is not 15V you still need a voltage divider to step down that voltage, for that we use R1 = 100Ω and R2 = 1.3KΩ. You need to remember that more than 1 V is going to be in the diode, so for our calculation we need to consider it. Vf = (V*R2)/(R1+R2), V = Vin - 1 = 17-1 = 16V and Vf = 15, Choosing a fix resistance R1 = 100Ω and solving the equation we find R2 = 1.5KΩ
  3. Finally to select the diode you need to calculate two times the maximum current and that would be the forward current (If) of your diode. Imax = Vf/R2 = 10mA and If = 2*Imax = 20mA

Our circuit meet the average voltage (Va) specification:

Va = (15)/(pi) = 4.77V considering the diode voltage or 3.77V without considering it

6 0
3 years ago
Plant scientists would not do which of the following?
zavuch27 [327]

Explanation:

i think option 4 is correct answer because itsrelated to animal not plants.

6 0
3 years ago
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A wooden pallet carrying 540kg rests on a wooden floor. (a) a forklift driver decides to push it without lifting it.what force m
kicyunya [14]

Answer:

The appropriate solution is "1481.76 N".

Explanation:

According to the question,

Mass,

m = 540 kg

Coefficient of static friction,

\mu_s = 0.28

Now,

The applied force will be:

⇒ F=\mu_s mg

By substituting the values, we get

       =0.28\times 540\times 9.8

       =1481.76 \ N

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2 years ago
Plot the function for . Notice that the function has two vertical asymptotes. Plot the function by dividing the domain of x into
elena-s [515]
This is a very very difficult one for me, let me get back to you with the proper answer.
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3 years ago
Find the number of Btu conducted through a wall in 8 hours. The wall is 8 feet high by 24 feet long and has a total R-value of 1
dedylja [7]

Answer:

ΔQ = 4930.37 BTu

Explanation:

given data

height h = 8ft

Δt = 8  hours

length L = 24 feet

R value = 16.2 hr⋅°F⋅ft² /Btu

inside temperature t1 = 68°F

outside temperature t2 = 16°F

to find out

number of Btu conducted

solution

we get here number of Btu conducted by this expression that s

\frac{\Delta Q}{\Delta t} =\frac{-A}{R} (t2 -t1)     ......................1

here A is area that is = h × L = 8 × 24 = 1492 ft²

put here value we get

\frac{\Delta Q}{8} =\frac{-192}{16.2} (16-68)

solve it we get

ΔQ = 4930.37 BTu

7 0
3 years ago
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