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3 years ago

In remote areas, your gps devices may lose reception. It’s a good idea to have a

2 answers:

4 0

Answer: MAP!!! it's always a good Idea to have a map nearby, cause you'll never know when you'll need it or like you said, lose reception

Serhud [2]3 years ago

3 0

Answer:

You will need a map, having a map is always very important when electronic gadgets don't work, but you can also take a compass with you.

Explanation:

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A polymeric extruder is turned on and immediately begins producing a product at a rate of 10 kg/min. An operator realizes 20 min

hodyreva [135]

Answer:

The plot of the function production rate m(t) (in kg/min) against time t (in min) is attached to this answer.

The production rate function M(t) is:

$m(t)=[H(t)\cdot10+H(t-20)\cdot5-H(t-80)\cdot14+H(t-81)\cdot9]kg/min$ (1)

The Laplace transform of this function is:

$\displaystyle m(s)=[\frac{10+5e^{-20s}-14e^{-80s}+9e^{-81s}}{s}]kg/min$ (2)

Explanation:

The function of the production rate can be considered as constant functions by parts in the domain of time. To make it a continuous function, we can use the function Heaviside (as seen in equation (1)). To join all the constant functions, we consider at which time the step for each one of them appears and sum each function multiply by the function Heaviside.

For the Laplace transform we use the following rules:

$\mathcal{L}[f(x)+g(x)]=\mathcal{L}[f(x)]+\mathcal{L}[g(x)]=F(s)+G(s)$ (3)

$\mathcal{L}[aH(x-b)]=\displaystyle\frac{ae^{-bs}}{s}$ (4)

4 0

4 years ago

The difference between ideal voltage source and the ideal current source

DENIUS [597]

An ideal voltage source provides no energy when it is loaded by an open circuit (i.e. an infinite impedance), but approaches infinite energy and current when the load resistance approaches zero (a short circuit). ... An ideal current source has an infinite output impedance in parallel with the source.

5 0

4 years ago

Read 2 more answers

7. A single-pole GFCI breaker is rated at

soldi70 [24.7K]

The answer to this question is C

3 0

3 years ago

Write what you already know about college majors. What are they? Can you think of any examples? When do you have to pick one? Ca

Mandarinka [93]

College majors are specific fields of study that help people prepare for career paths and learn content related to that subject. Some college majors would criminal justices, forensic science, gender studies, engineering, chemistry, and more. You should generally begin to research in your junior year of high school and select one by the beginning or your senior year for college applications. Once you get to college you can change your major.

5 0

3 years ago

Read 2 more answers

The transfer function of a linear system is defined as the ratio of the Laplace transform of the output function y(t) over the r

faltersainse [42]

Answer:

H(s) = Y(s)/G(s) = 1/(s² + 8s + 6)

Explanation:

Since we are required to determine the transfer function G(s) and Y(s) = G(s)H(s). So, H(s) = Y(s)/G(s).

Since our system is given as y′′(t) + 8y′(t) +6y(t) = g(t), t>0 with all initial condition zero, that is, y(0) = 0, y"(0) = 0 and g(0) = 0.

Taking the Laplace transform of both the left hand side and right hand side of the equation, we have

y′′(t) + 8y′(t) +6y(t) = g(t),

L{y′′(t) + 8y′(t) +6y(t)} = L{g(t)}

L{y′′(t)} + L{8y′(t)} + L{6y(t)} = L{g(t)}

L{y′′(t)} + 8L{y′(t)} + 6L{y(t)} = L{g(t)}

[s²Y(s) - sy(0) - y'(0)] + 8[sY(s) - y(0)] + 6Y(s) = G(s)

[s²Y(s) - s(0) - 0] + 8[sY(s) - 0] + 6Y(s) = G(s)

s²Y(s) + 8sY(s) + 6Y(s) = G(s)

(s² + 8s + 6)Y(s) = G(s)

Y(s)/G(s) = 1/(s² + 8s + 6)

So, H(s) = Y(s)/G(s) = 1/(s² + 8s + 6)

6 0

3 years ago