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oksano4ka [1.4K]
3 years ago
13

How many moles of aluminum are in 95.0 grams of aluminum

Chemistry
1 answer:
wlad13 [49]3 years ago
6 0

Answer:

26.981538 just looked at it.

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Calculate the percentage of yield when 20 grams of sodium chloride solution reacts with an excess amount of silver nitrate solut
Lady bird [3.3K]

%yield = 91.8

<h3>Further explanation</h3>

Given

20 g NaCl

45 g AgCl

Required

%yield

Solution

Reaction

NaCl + AgNO₃ ⇒ AgCl + NaNO₃

mol NaCl :

= mass : MW

= 20 g : 58,44 g/mol

= 0.342

mol AgCl from equation :

= 1/1 x mol NaCl

= 1/1 x 0.342

= 0.342

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= mol x MW

= 0.342  x 143,32 g/mol

= 49.02 g

%yield = (actual/theoretical) x 100%

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7 0
3 years ago
Willam adds two values following the rules for using significant figures in computations
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Hope that helps!!!
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