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djyliett [7]
3 years ago
8

An inventor claims to have developed a refrigerator that at steady state requires a net power input of 1.1 horsepower to remove

12,000 Btu/h of energy by heat transfer from the freezer compartment at 0°F and discharge energy by heat transfer to a kitchen at 70°F. Evaluate this claim.
Engineering
1 answer:
Lynna [10]3 years ago
6 0

Answer:

The inventor's claim is false in the sense that no thermal machine can violate the first thermodynamic law.

Explanation:

The inventor's claim could not be possible as no thermal machine can transfer more heat than the input work consumed. If we expose the thermal efficiency:

n=Q out / W in

Where Q and W both must be in the same power unit, so we will convert the remove heat from BTU/hr to hp:

12000 BTU/hr = 4.72 hp

Therefore by comparing, we notice that the removing heat of 4.75 hp is large than the delivered work of 1.11 hp. By evaluating the efficiency:

[tex]n=4.75 hp / 1.1 hp  = 4.3 > 1[/tex]

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Why is it important to know the accuracy and precision of a measuring device? Do you think that the dial caliper manufacturer’s
Leto [7]

Answer:

Accuracy and precision allow us to know how much we can rely on a measuring device readings. ±.001 as a "accuracy" claim is vague because there is no unit next to the figure and the claim fits better to the definition of precision.

Explanation:

Accuracy and Precision: the golden couple.

Accuracy and precision are key elements to define if a measuring device is reliable or not for a specific task. Accuracy determines how close are the readings from the ideal/calculated values. On the other hand, precision refers to repeatability, that is to say how constant the readings of a device are when measuring the same element at different times. One of those two key concepts may not fulfill the criteria for measuring tool to be used on certain engineering projects where lack of accuracy (disntant values from real ones) or precision (not constant readings) may lead to malfunctons and severe delays on the project development.

±.001 what unit?

The manufacturer says that is an accuracy indicator, nevertheless there is now unit stated so this is not useful to see how accurate the device is. Additionally, That notation is more used to refer to device tolerances, that is to say the range of possible values the instrument may show when reading and element. It means it tells us more about the device precision during measurments than actual accuracy. I would recommend the following to the dial calipers manufacturers to better explain its measurement specifications:

  1. Use  ±.001 as  a reference for precision. It is important to add the respective unit for that figure.
  2. Condcut test to define the actual accuracy value an present it using one of the common used units for that:  Error percentage or ppm.

3 0
3 years ago
A spherical container made of steel has 20 ft outer diameter and wal thickness of 1/2 inch. Knowing the internal pressure is 50
anastassius [24]

Answer:

maximum normal stress = 5975 psi

maximum shear stress = 2987.50 psi

Explanation:

Given data

dia = 20 ft

wall thickness = 1/2 inch

internal pressure  = 50 psi

To find out

the maximum normal stress and the maximum shearing stress

Solution

By the Mohr's circle we will find out shear stress

first we calculate inner radius

i.e. r = (diameter/2) - t

r = (20 × 12 in )/2 - ( 1/2 )

r =  120 - 0.5 = 119.5 inch

Now we find out maximum normal stress by given formula

normal stress = ( internal pressure× r ) / 2 t

normal stress = ( 50×119.5 ) / 2 × 0.5

maximum normal stress = 5975 psi

and minimum normal stress is 0, due to very small radius

and maximum shear stress will be

shear stress = ( maximum normal stress - minimum normal stress ) / 2

shear stress = ( 5975- 0 ) / 2

maximum shear stress = 2987.50 psi

5 0
3 years ago
g Four primary sedimentation basins are designed for total average flow of 1.2 m3/s. The TSS concentration in the primary treate
fiasKO [112]

Answer:

Capacity for the sludge pump = 0.217 m³/min

Explanation:

Detailed explanation is given in the attached document.

5 0
3 years ago
The net negative charge flowing through a device varies as q(t) = 2.2 t2 C. Find the current through the device at t = 0, 0.5, a
Leni [432]

Answer:

The current at t= 0 sec, is 0 A

The current at t= 0.5 sec, is 2.2 A

The current at t= 1 sec, is 4.4 A

Explanation:

Given that

q(t) = 2.2 t²

We know that:- the change in the charge w.r.t. time is known as current. So,

I=\dfrac{dq}{dt}

q(t) = 2.2 t²

\dfrac{dq}{dt}= 4.4 t

I= 4.4 t

1.

t = 0 s :

I = 4.4 x 0 = 0 A

<u>Therefore, the current at t= 0 sec, is 0 A</u>

2 .

t= 0.5 s :

I = 4.4 x 0.5 = 2.2 A

<u>Therefore, the current at t= 0.5 sec, is 2.2 A</u>

3.

t= 1 s

I = 4.4 x 1 =4.4 A

<u>Therefore, the current at t= 1 sec, is 4.4 A</u>

4 0
3 years ago
An automatic control mode that uses proportional integral and derivative control must at least specify_ and tuning parameters​
guapka [62]

Answer:

Set point

Explanation:

PID control compares a measurement to a specified set point.  The difference between those values is input into tuning parameters that send a signal to the process to make the correction.

6 0
3 years ago
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