Answer:
The higher the temperature, the more soluble most ionic solids are in water
As you cool a saturated solution from high temperature to low temperature, solids start to crystallize out of solution if you achieve a supersaturated solution.
If you raise the temperature of a saturated solution, you can (usually) add more solute and make the solution even more concentrated.
Explanation:
For many ionic solids, solubility in water increases with increase in the temperature of the solution.
This implies that increasing the temperature allow more solute to dissolve in the solvent, supersaturation may be achieved by so doing. As the solution is cooled, the solid crystalizes out of solution hence the answers above.
<u>Answer:</u> The final temperature of the copper is 95°C.
<u>Explanation:</u>
To calculate the final temperature for the given amount of heat absorbed, we use the equation:

Q = heat absorbed = +133 J (heat is added to the system)
m = mass of copper = 5.00 g
c = specific heat capacity of copper = 0.38 J/g ° C


Putting values in above equation, we get:

Hence, the final temperature of the copper is 95°C.
Answer:
Option C. the sharing of electrons between atoms
Explanation:
Covalent bond is a type of bond in which the reacting element share their valence electrons in order to attain the noble gas configuration.
Transition metals usually
Answer: Option (c) is the correct answer.
Explanation:
HF is a weak acid and not a strong acid. This is because fluorine is a highly electronegative atom and when it combines with a hydrogen atom then it will attract the valence electron of hydrogen atom more towards itself.
As a result, it will not dissociates easily to give hydrogen ion. Hence, it acts as a weak acid.
A neutralization reaction is defined as a reaction in which an acid reacts with a base to give salt and water. For example, 
It is true that, spectator ions "appear in the total ionic equation for a reaction, but not in the net ionic equation".
Titration is defined as a process in which concentration of an unknown solution is determined using a solution of known concentration.
Thus, we can conclude that the statement HF, HCl, and HNO3 are all examples of strong acids, is false.