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2 years ago

Describe the oceanic crust NO LINKS

Chemistry

2 answers:

klasskru [66]2 years ago

7 0

Answer:

Oceanic crust, the outermost layer of Earth’s lithosphere that is found under the oceans. Oceanic crust is constantly formed at mid-ocean ridges, where tectonic plates are tearing apart from each other.

Explanation:

torisob [31]2 years ago

4 0

Answer:

oceanic crust is the relatively thin part of the earth's crust which underlies the ocean basins. It is geologically young compared with the continental crust and consists of basaltic rock overlain by sediments

Explanation:

I hope this helped ;)

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Iridium has only two naturally occurring isotopes. Ir-191 with arelative mass of 190.96058 and Ir-193 with a relative mass of192

OLEGan [10]

Answer: The fractional abundance of Ir-191 is 0.372

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

Let the fractional abundance of Ir-191 be x and that of Ir-193 isotope be (1-x)

For isotope 1 (Ir-191):

Mass of isotope 1 = 190.96058 amu

Fractional abundance of Ir-191 = x

For isotope 1 (Ir-193):

Mass of isotope 1 = 192.96292 amu

Fractional abundance of Ir-193 = (1 - x)

Average atomic mass of iridium = 192.217 amu

Putting values in equation 1, we get:

$192.217=[(190.96058\times x)+(192.96292\times (1-x))]\\\\x=0.372$

Hence, the fractional abundance of Ir-191 is 0.372

6 0

3 years ago

Choose the products that complete the reaction. The chemical equations may not be balanced. HCl + NaOH ? NaCl + H2O NaCl + CO2 +

Aliun [14]

Answer:

a- NaCl + H20

3 0

3 years ago

The pressure needed to pump blood back to the heart is produced by the _____.

PolarNik [594]

Answer:

A. body muscles

The pressure needed to pump blood back to the heart is produced by the body muscles .

4 0

2 years ago

A solution is prepared by dissolving 91.7 g fructose in 545 g of water. Determine the mole fraction of fructose if the final vol

oee [108]

Answer:

Mole fraction = 0,0166

Explanation:

Mole fraction is defined as mole of a compound per total moles of the mixture. In the solution, the solute is fructose and the solvent is water. That means you need to find moles of fructose and moles of water.

The molecular mass of fructose is 180,16g/mol and mass of water is 18,02 g/mol. Using these values:

91,7g fructose × (1mol / 180,16g) = 0,509 moles of fructose

545g water × (1mol / 18,02g) = 30,24 moles of water

Thus, mole fraction of fructose is:

$\frac{0,509 moles}{0,509mol + 30,24mol} = 0,0166$

Mole fraction = 0,0166

I hope it helps!

5 0

2 years ago

Which is the smallest part of a compound called?

lidiya [134]

The answer is molecule

6 0

3 years ago

Read 2 more answers