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enot [183]
3 years ago
10

Which element is an example of a metalloid? A) gold B) helium C) iron D) silicon

Chemistry
2 answers:
kondaur [170]3 years ago
8 0

D silicon that is the answer.

Ulleksa [173]3 years ago
5 0

D) Silicon is an example of a metalloid.

It has some of the properties of metals and some of the properties of nonmetals.

In the Periodic Table, metalloids sit on either side of a zig-zag line separating metals from nonmetals.

In the diagram below, Fe and Au are metals, while He is a nonmetal.

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How many electrons are in an atom with the electron<br> configuration of 1s 2s 2p 3s!?
Viefleur [7K]

Answer:

11

Explanation:

electronic configuration = 1s^2, 2s^2, 2p^6, 3s^1

therefore total electrons = 2+2+6+1 = 11

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em> </em><em>youu</em><em> </em>。◕‿◕。

6 0
3 years ago
Why is the boiling point of water a characteristic physical property but the temperature and the volume of a glass of water isn’
Alexeev081 [22]
Hi, the temperature of water is not a physical characteristic because it does not tell us a lot about the substance.
4 0
3 years ago
If a gas occupies 1532.7 mL at standard temperature, what volume does it occupy at 49.4 ºC if the pressure remains constant?
ElenaW [278]

Answer:

a. 1810mL

Explanation:

When conditions for a gas change under constant pressure (and the number of molecules doesn't change), it follows Charles' Law:

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}  where the temperatures must be measured in Kelvin

To convert from Celsius to Kelvin, add 273, or use the equation:  T_C+273=T_K

For this problem, one must also recall that standard temperature is 0°C (or 273K).

So, T_1 = 273[K], and T_2 = (49.4+273)[K]=322.4[K].

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

\dfrac{(1532.7[mL])}{(273[K])}=\dfrac{V_2}{(322.4[K])}

\dfrac{(1532.7[mL])}{(273[K\!\!\!\!\!{-}])}(322.4[K\!\!\!\!\!{-}] )=\dfrac{V_2}{(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})}(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})

1810.04571428[mL]=V_2

Adjusting for significant figures, this gives V_2=1810[mL]

4 0
2 years ago
There are 4.184___<br> in a Joule of energy
Alinara [238K]

Answer: calories?

Explanation: but isn’t it 1 calorie = 4.184 joules of energy

4 0
3 years ago
A 0. 462 g sample of a monoprotic acid is dissolved in water and titrated with 0. 180 m koh. what is the molar mass of the acid
Len [333]

The molar mass of the acid if 28. 5 ml of the koh solution is required to neutralize the sample is 90.23g/mol.

<h3>For the calculation of molarity of solution</h3>

Molarity = (moles of solute/volume of solution) × 1000

Given,

Molarity of KOH solution = 0.180 M

Volume of solution = 28.5 mL

0.180 = (moles of KOH/ 28.5) × 1000

Moles = (0.18× 28.5)/1000

= 0.00513 mol

<h3>Chemical equation for the reaction</h3>

HA + KOH ------- KA + H2O

1 moles of KOH reacts with 1 moles of HA.

So, 0.00513 moles of KOH react with 0.00513 moles of HA.

<h3>To calculate the molar mass for given number of moles</h3>

Number of moles= given mass/ Molar mass

Given,

Mass of HA = 0.462 g

Moles of HA = 0.00512 mol

0.00512 = 0.462/ Molar mass

Molar mass = 90.23 g/ mol.

Thus the molar mass of HA required to neutralize the 28.5 mL of KOH is 90.23g/mol.

learn more about molar mass or moles:

brainly.com/question/26416088

#SPJ4

3 0
1 year ago
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