MThe heat energy required to raise the temperature of 0.36Kg of copper from 22 c to 60 c is calculate using the following formula
MC delta T
m(mass)= 0.360kg in grams = 0.360 x1000 = 360 g
c(specific heat energy) = 0.0920 cal/g.c
delta T = 60- 23 = 37 c
heat energy is therefore= 360g x0.0920 cal/g.c x 37 c= 1225.44 cal
Is there answer choices ??
Answer:
According to conservation of matter, there should be equal amounts of all elements on both the reactant and product side.
Reactant:
1 Ca
1 C
1 O
Product:
1 Ca
1 C
3 O
Therefore, your friend is right because the law of conservation of matter is not followed in this chemical equation.
Explanation:
