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Fittoniya [83]
3 years ago
9

Please help me :( thank you so much and if you can show work I would really appreciate it

Chemistry
1 answer:
Katyanochek1 [597]3 years ago
6 0

Answer:

D

Explanation:

On the left hand side there are a total of 4 hydrogen and 2 oxygen but on the right hand side there Is only 2 hydrogen and 1 oxygen

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6CO2 + 6 H2O —> C6H12O6 + 6O2
PilotLPTM [1.2K]

Answer:

The answer to your question is 0.5 moles

Explanation:

Data

moles of Glucose = ?

moles of carbon dioxide = 3

Balanced chemical reaction

                6CO₂  +  6H₂O   ⇒   C₆H₁₂O₆  +  6O₂

Process

To solve this problem, use proportions, and cross multiplication.

Use the coefficients of the balanced equation.

                6 moles of CO₂ ----------------- 1 mol of C₆H₁₂O₆

                3 moles of CO₂ ----------------    x

                    x = (3 x 1) / 6

-Simplification

                    x = 3/6

-Result

                   x = 0.5 moles of Glucose

3 0
3 years ago
What is the approximate mass of one mole of oxygen gas (O2)?
fenix001 [56]

The correct answer is B.

1 mol O2  x  15.999 O2/ 1 mol O2 = 15.999 O2

16 O2 when rounded.

3 0
3 years ago
The most useful ore of aluminum is bauxite, in which Al is present as hydrated oxides, Al2O3 * xH2O.
lesantik [10]

Answer:

44.7 kWh

Explanation:

Let's consider the reduction of Al₂O₃ to Al in the Bayer process.

6 e⁻ + 3 H₂O + Al₂O₃ → 2 Al + 6 OH⁻

We can establish the following relations:

  • The molar mass of Al is 26.98 g/mol.
  • 2 moles of Al are produced when 6 moles of e⁻ circulate.
  • 1 mol of e⁻ has a charge of 96468 c (Faraday's constant).
  • 1 V = 1 J/c
  • 1 kWh = 3.6 × 10⁶ J

When the applied electromotive force is 5.00 V, the energy required to produce 3.00 kg (3.00 × 10³ g) of aluminum is:

3.00 \times 10^{3} gAl.\frac{1molAl}{26.98gAl} .\frac{6mole^{-}}{2molAl}.\frac{96468c}{1mole^{-}}.\frac{5.00J}{c}.\frac{1kWh}{3.6 \times 10^{6}J} =44.7kWh

6 0
3 years ago
Which two factors that influence weather are caused by the uneven heating of
just olya [345]
B, sorry if i am wrong.
8 0
2 years ago
Read 2 more answers
What is the molarity of an aqueous solution containing 1.5 moles of calcium chloride in 2.75 L of solution? A. 0.004 M B. 0.55 M
kondor19780726 [428]

Answer:

B. 0.55 M

Explanation:

Step 1: Given data

  • Moles of calcium chloride (solute): 1.5 mol
  • Volume of solution: 2.75 M

Step 2: Calculate the molarity of the aqueous solution

The molarity is a way to express the concentration of a solution. It is equal to the quotient between the moles of solute and the liters of solution.

M = moles of solute / liters of solution

M = 1.5 mol / 2.75 L = 0.55 mol/L = 0.55 M

6 0
2 years ago
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