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Fittoniya [83]
3 years ago
9

Please help me :( thank you so much and if you can show work I would really appreciate it

Chemistry
1 answer:
Katyanochek1 [597]3 years ago
6 0

Answer:

D

Explanation:

On the left hand side there are a total of 4 hydrogen and 2 oxygen but on the right hand side there Is only 2 hydrogen and 1 oxygen

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Answer:

-800 kJ/mol

Explanation:

To solve the problem, we have to express the enthalpy of combustion (ΔHc) in kJ per mole (kJ/mol).

First, we have to calculate the moles of methane (CH₄) there are in 2.50 g of substance. For this, we divide the mass into the molecular weight Mw) of CH₄:

Mw(CH₄) = 12 g/mol C + (1 g/mol H x 4) = 16 g/mol

moles CH₄ = mass CH₄/Mw(CH₄)= 2.50 g/(16 g/mol) = 0.15625 mol CH₄

Now, we divide the heat released into the moles of CH₄ to obtain the enthalpy per mole of CH₄:

ΔHc = heat/mol CH₄ = 125 kJ/(0.15625 mol) = 800 kJ/mol

Therefore, the enthalpy of combustion of methane is -800 kJ/mol (the minus sign indicated that the heat is released).

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3 years ago
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The chemical equation for the reaction of sodium hypochlorite and water follows:

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