V=IxR
v =0.042x2.2
potential difference =0.0924volts
Answer:
Well, to be perfectly honest in my humble opinion, of course without offending anyone who thinks different from my point of view but also by looking into this matter in a different perspective and without condemning one's view and by trying to make it objectified and considering each and everyone's valid opinion, I honestly believe that I completely forgot what I was going to say.
Electrical kettle:
P = 2 KW = 2000 W
U = 200 V
⇒ I = P/U = 2000 / 200 = 10 A
We apply the Law of Ohm:
R = U / I = 200V / 10A = <u>20 Ω</u>
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Electrical heater:
P = 1 KW = 1000 W
U = 240 V
⇒ I = P/U = 1000 / 240 = 4,16 A
We apply the Law of Ohm:
R = U / I = 240V / 4,16A = <u>57,69 Ω</u>
<u>Answer:</u>
The device with the highest resistance is <u>the electric heater.</u>
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For a certain interval of time, an object is acted on by a constant non-zero force. For this interval of time . . . . .
A. The object is at rest. No. From F=ma, if F is not zero, the object can't remain at rest.
<em>B.</em> <em>The object's velocity changes.</em> <em>Yes.</em> From F=ma, if F is not zero, there must be acceleration.
C. The object's velocity can only increase. No. It might decrease.
D. The object is moving with constant velocity. No. From F=ma, if F is not zero, there must be acceleration.
<em>E.</em> <em>The object is accelerating.</em> <em>Yes.</em> From F=ma, if F is not zero, there must be acceleration.
This question is solved using an available similar problem as data provided for the forces was not given.
Repeat the same steps outlined for your problem.
Regards.
Answer:
F = 1.598 KN , Q = 90 degree (+ y-axis)
Explanation:
Sum of Forces in x-direction to the left (+)
2 cos (30) + 3cos (60) + F*cos (Q) = F_a ..... 1
Sum of Forces in y-direction to the up (+)
2 sin (30) + F*sin (Q) - 3 sin (60) ...... 2
Using Eq 2 and solve:
F*sin (Q) = 1.598 KN
F_min when sin (Q) is max, max possible value of sin(Q) = 1 @ Q = 90 degrees.
Hence,
F_min = 1.598 KN
Using Eq 1 @ Q = 90 degrees and F = 1.598 KN:
F_a = 2 cos (30) + 3cos (60) = 3.2 KN
