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3 years ago

I am bored someone talk to me please

Physics

2 answers:

qaws [65]3 years ago

5 0

Hey what’s up Lol ok

sammy [17]3 years ago

3 0

Answer:

uh Hi

Step by Step Explenation:

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If something is 50% efficient, how many joules of wasted energy will there be if 750J of energy is put in?

evablogger [386]

Answer:

375J of wasted energy

Explanation:

Efficiency=work output/work input×100%

50=w.o/750×100

750×50=100w.o

w.o=750×50/100

w.o=75×5

w.o=375J

Wasted energy=750J-375J

=375J

Aliter

If the machine is 50% efficient then it is also 50% inefficient

50%×750J=375J

5 0

3 years ago

Ligaments are important because they provide joints with:

lora16 [44]

Answer:

the answer is B. it's too easy

4 0

3 years ago

Consult Multiple-Concept Example 11 for background material relating to this problem. A small rubber wheel on the shaft of a bic

Papessa [141]

Answer:

$Emf=24.4V$

Explanation:

From the question we are told that:

Angular speed $\omega=40*\omega'$

Radius $r=0.33m$

No. Turns $N=163$

Area $A= 3.23 * 10^{-3} m^2$

Magnetic field. $B=0.0948T$

Acceleration $a=0.60m/s^2$

Time $t=6.72s$

Generally the equation for momentum is mathematically given by

$\omega'=\omega_o+\frac[a}{r}t$

$\omega'=0+\frac{0.60}{0.33}*6.72$

$W=12.22rad/s^2$

Therefore

$\omega=Aw$

$\omega=12.22*40$

$\omega=488.7rads/s$

Generally the equation for Peak emf is mathematically given by

$Emf=NBA \omega$

$Emf=163*0.0948* 3.23 * 10^{-3} m^2*488.7rads/s$

$Emf=24.4V$

3 0

3 years ago

Place thermometers near the edge of the table for easy retrieval.

Maurinko [17]

This is a true and false question correct or did you accidentally put two truths ??

7 0

4 years ago

What is the speed of light (in m/s) in air? (Enter your answer to at least four significant figures. Assume the speed of light i

jenyasd209 [6]

Answer:

The speed of light in air is 2.996x10⁸ m/s, and polystyrene is 1.873x10⁸ m/s.

Explanation:

To find the speed of light in air and in polystyrene we need to use the following equation:

$c_{m} = \frac{c}{n}$

Where:

$c_{m}$ : is the speed of light in the medium

n: is the refractive index of the medium

In air:

$c_{a} = \frac{c}{n_{a}} = \frac{2.997 \cdot 10^{8} m/s}{1.0003} = 2.996 \cdot 10^{8} m/s$

In polystyrene:

$c_{p} = \frac{c}{n_{p}} = \frac{2.997 \cdot 10^{8} m/s}{1.6} = 1.873 \cdot 10^{8} m/s$

Therefore, the speed of light in air is 2.996x10⁸ m/s, and polystyrene is 1.873x10⁸ m/s.

I hope it helps you!

8 0

3 years ago