I am bored someone talk to me please

Physics

2 answers:

qaws [65]3 years ago

5 0

Hey what’s up Lol ok

sammy [17]3 years ago

3 0

Answer:

uh Hi

Step by Step Explenation:

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In reaching her destination, a backpacker walks with an average velocity of 1.22 m/s, due west. This average velocity results be

Vinvika [58]

Wow! 2.95m/s is a mighty fast pace for a backpacker. Must have one of those Star Wars anti-gravity packs. Also, I would be curious as to why she passed her destination and then walked back.
Anyway, it goes like this: 
Say the time walking east is 't', and the total time is 'T'. 
Then 5340 m + .511 t = 1.43 T 
(This assumes that velocity is positive in both directions) 
Two unknowns in one equation. But you also know that the time spent walking west is 
5340m/ 2.95m/s = 1810 sec. 
and the total time T = 1810 +t 
Substitute this into the first equation, and you can solve for t = 3092 sec. 
Then T = 4902 sec. and distance walked east is .511t = 1580m.

8 0

4 years ago

How would you rate your mental health from a scale of 1 (lowest) to 5 (highest) and why?

madam [21]

For me 3 because I have depression for u I do not know only u can decide that

7 0

3 years ago

The Starship Enterprise speeds past an asteroid at 0.920c. If an observer on the asteroid sees 10.0 seconds pass on her watch, h

lukranit [14]

Answer:

25.52 seconds

Explanation:

Speed of space ship = 0.92 c = v

c = Speed of light

Time observed from asteroid = Δt = 10 seconds

Time dilation

$\Delta t'=\frac{\Delta t}{\sqrt{1-\frac {v^2}{c^2}}}\\\Rightarrow \Delta t'=\frac{10}{\sqrt{1-\frac {0.92^2c^2}{c^2}}}\\\Rightarrow \Delta t'=\frac{10}{\sqrt{1-0.92^2}}\\\Rightarrow \Delta t'=25.52\ s$

∴ Time interval be if measured by an observer on the Enterprise would be 25.52 seconds

5 0

4 years ago

Is 250 000 miles from the earth to the moon" is a qualitative Observation TRUE Or false

lys-0071 [83]

Answer:

True

Explanation:

3 0

3 years ago

A gun is fired vertically into a 1.40 kg block of wood at rest directly above it. If the bullet has a mass of 21.0 g and a speed

ahrayia [7]

To solve this problem we will use the theorems related to the conservation of momentum to determine the final speed of the system, once the bullet hits it. From there, we will calculate with the kinematic equations of linear motion, the height traveled with that speed. The conservation of momentum say us that,

$m_1u_1+m_2u_2 = (m_1+m_2)v_f$